org.apache.xpath.Expression.isStableNumber()方法的使用及代码示例

x33g5p2x  于2022-01-19 转载在 其他  
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本文整理了Java中org.apache.xpath.Expression.isStableNumber()方法的一些代码示例,展示了Expression.isStableNumber()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Expression.isStableNumber()方法的具体详情如下:
包路径:org.apache.xpath.Expression
类名称:Expression
方法名:isStableNumber

Expression.isStableNumber介绍

[英]Tell if this expression returns a stable number that will not change during iterations within the expression. This is used to determine if a proximity position predicate can indicate that no more searching has to occur.
[中]说明此表达式是否返回在表达式内迭代期间不会更改的稳定数字。这用于确定邻近位置谓词是否可以指示不必再进行搜索。

代码示例

代码示例来源:origin: robovm/robovm

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: xalan/xalan

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: MobiVM/robovm

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: ibinti/bugvm

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: com.bugvm/bugvm-rt

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: com.mobidevelop.robovm/robovm-rt

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: org.apache.xalan/com.springsource.org.apache.xalan

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.xalan

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: org.apache.karaf.bundles/org.apache.karaf.bundles.xalan-2.7.1

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: com.gluonhq/robovm-rt

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

代码示例来源:origin: FlexoVM/flexovm

if(m_predicates[i].isStableNumber() && i == nPredicates - 1)

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