算法第五天-01的概率问题+mysql复习

x33g5p2x  于2022-05-25 转载在 Mysql  
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01由不等概率转变为等概率:

  1. package Random.随机函数;
  2. /**
  3. * 不等概率的01----->等概率01
  4. */
  5. public class Test2 {
  6. public static int x(){
  7. return Math.random() < 0.84? 0 : 1;
  8. }
  9. /**
  10. * 等概率的01 先判断一次,ans要是是0,在判断一次,要是还是0,返回0,要是1就重来一次,同理1也这样,01就是等概率
  11. * @return
  12. */
  13. public static int y(){
  14. int ans = 0;
  15. do {
  16. ans = x();
  17. }while (ans==x());
  18. return ans;
  19. }
  20. }

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MYSQL

这个题是三个表,我们的思维就是化成两个表,将其中两个表通过内连接合并,然后再和第一个表左连接查询

  1. SELECT e.last_name, e.first_name, b.dept_name
  2. FROM employees AS e
  3. LEFT JOIN (SELECT d.dept_no,d.dept_name,de.emp_no
  4. FROM departments AS d
  5. INNER JOIN dept_emp AS de
  6. ON d.dept_no=de.dept_no
  7. ) AS b
  8. ON e.emp_no=b.emp_no;

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