【题目】一个启动键、一个打击键，数码管4位，显示数字从0循环显示到99, 每0.5秒增加一个数字，中间随时按下按键，按下按键时若恰好循环数字尾数为3和4，每成功一次计1分，1次循环结束，分值大于10分则显示 （C 分值 倒C） 表示胜利，否则显示FALE表示失败。

【代码】基本实现题目需要，但是碰到一个问题：按键缓存影响计数，如何解决？

#include<stdio.h>
#include<conio.h>
#include<windows.h>
void gotoXY(int x, int y)
{
	COORD coord = {(short)x, (short)y};
	SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}
void saymsg(int x, int y, char*s)
{
	gotoXY(x,y);
	printf("%s",s);
} 
void display(int x, int y, int n)
{
	char num[16][6][6] = {
	{{" ___ "},{"|   |"},{"|   |"},{"|   |"},{"|___|"}},
	{{"     "},{"    |"},{"    |"},{"    |"},{"    |"}},
	{{" ___ "},{"    |"},{" ___|"},{"|    "},{"|___ "}},
	{{" ___ "},{"    |"},{" ___|"},{"    |"},{" ___|"}},
	{{"     "},{"|   |"},{"|___|"},{"    |"},{"    |"}},
	{{" ___ "},{"|    "},{"|___ "},{"    |"},{" ___|"}},
	{{" ___ "},{"|    "},{"|___ "},{"|   |"},{"|___|"}},
	{{" ___ "},{"    |"},{"    |"},{"    |"},{"    |"}},
	{{" ___ "},{"|   |"},{"|___|"},{"|   |"},{"|___|"}},
	{{" ___ "},{"|   |"},{"|___|"},{"    |"},{" ___|"}},
	{{" ___ "},{"|    "},{"|    "},{"|    "},{"|___ "}},
	{{" ___ "},{"    |"},{"    |"},{"    |"},{" ___|"}},
	{{" ___ "},{"|    "},{"|___ "},{"|    "},{"|    "}},
	{{" ___ "},{"|   |"},{"|___|"},{"|   |"},{"|   |"}},
	{{"     "},{"|    "},{"|    "},{"|    "},{"|___ "}},
	{{" ___ "},{"|    "},{"|___ "},{"|    "},{"|___ "}},
	};
	
	for (int i=0;i<5;i++)
		saymsg(x,y+i,num[n][i]);
	}
int main()
{
	int x = 30, y = 8, key;
	int scores = 0;
	display(x,y,10);
	display(x+6,y,0);
	display(x+12,y,0);
	display(x+18,y,11);
	saymsg(x,y+6,(char*)"回车键开始，空格键计数");
	while (1){
		if (kbhit()){
			key = getch();
			if (key==13)
				break;
		}
	}
	for (int i=0;i<10;i++){
		display(x+6,y,i);
		for (int j=0;j<10;j++){
			display(x+12,y,j);
			if (kbhit()) {
				key = getch();
				fflush(stdin); 
				//按键缓存影响计数如何解决？ 
				if(key==32 && (j==3||j==4))
					scores++;
				key = 0; 
				//以下两行测试用 
				gotoXY(x,y+9);
				printf("%d",scores);
				}
			Sleep(500);
			
		}
	}
	if (scores>10){
		display(x+6,y,11);
		display(x+12,y,11);
		saymsg(x,y+9,(char*)"Victory!\n");
	}
	else{
		for (int i=0;i<4;i++)
			display(x+i*6,y,i+12);
		saymsg(x,y+9,(char*)"FAIL\n");
	}
		
	return 0;
}

关于清理按键缓存除了用

fflush(stdin);

还试了：

rewind(stdin);
setbuf(stdin, NULL);

甚至还试了中断：

union REGS regs;
regs.h.ah = 0x0c;
regs.h.al = 0;
intdos(&regs, &regs);

好像都不管用，试了很多个办法都没成功，经过的达人来指点一下吧。