您可以将应用程序参数传递到spark submit中，如下所示。。
spark-submit的通用语法

./bin/spark-submit \
      --class <main-class> \
      --master <master-url> \
      --deploy-mode <deploy-mode> \
      --conf <key>=<value> \
      ... # other options
      <application-jar> \
      [application-arguments]

您可以使用file.txtschema1.txt（或）file1.txtscehma2.txt来代替[application arguments]
file.txt是第一个参数，schema1.txt是第二个参数。
在应用程序代码中，可以

def main(args: Array[String]) : Unit = {
     val inputFile = args(0);
     val schemaFile = args(1);
     val schemaFileasString = // open FileInoutStream and read whole schema data from**schemaFile**as string 
     val schema = SchemaConverter.convertContent(schemaFileasString)
     //create spark session and provide all the parameter properly
    import spark.implicits._
    val rdd = spark.sparkContext.wholeTextFiles(inputFile)
    val validJsonRdd = rdd.flatMap(_._2.replace(" ", "").replace("\n", "").replace(":value", ":\"value\"").replace("}{", "}\n{").split("\n"))

     spark.read
      .option("multiLine", true)
      .schema(schema)
      .json(validJsonRdd)
      .show()
   }

参考文献：
https://github.com/zalando-incubator/spark-json-schema
https://spark.apache.org/docs/latest/submitting-applications.html