这是我的密码：

from pyspark.sql import *

department1 = Row(id='123456', name='Computer Science')
department2 = Row(id='789012', name='Mechanical Engineering')

Employee = Row("firstName", "lastName", "email", "salary")
employee1 = Employee('michael', 'armbrust', 'no-reply@berkeley.edu', 100000)
employee2 = Employee('xiangrui', 'meng', 'no-reply@stanford.edu', 120000)

departmentWithEmployees1 = Row(department=department1, employees=[employee1, employee2])
departmentWithEmployees2 = Row(department=department2, employees=[employee1, employee2])

departmentsWithEmployeesSeq1 = [departmentWithEmployees1, departmentWithEmployees2]
df1 = spark.createDataFrame(departmentsWithEmployeesSeq1)

我想在数组中加入firstname和lastname。

from pyspark.sql import functions as sf
df2 = df1.withColumn("employees.FullName", sf.concat(sf.col('employees.firstName'), sf.col('employees.lastName')))
df2.printSchema()

root
 |-- department: struct (nullable = true)
 |    |-- id: string (nullable = true)
 |    |-- name: string (nullable = true)
 |-- employees: array (nullable = true)
 |    |-- element: struct (containsNull = true)
 |    |    |-- firstName: string (nullable = true)
 |    |    |-- lastName: string (nullable = true)
 |    |    |-- email: string (nullable = true)
 |    |    |-- salary: long (nullable = true)
 |-- employees.FullName: array (nullable = true)
 |    |-- element: string (containsNull = true)

我的新列fullname在父级，如何将它们放入数组中。

root
 |-- department: struct (nullable = true)
 |    |-- id: string (nullable = true)
 |    |-- name: string (nullable = true)
 |-- employees: array (nullable = true)
 |    |-- element: struct (containsNull = true)
 |    |    |-- firstName: string (nullable = true)
 |    |    |-- lastName: string (nullable = true)
 |    |    |-- email: string (nullable = true)
 |    |    |-- salary: long (nullable = true)
 |    |    |-- FullName: string (containsNull = true)