如何在spark中将一列字符串日期转换为一列unix epochs

zpqajqem 于 2021-05-27 发布在 Spark

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我是spark和scala的新手，我想把一列字符串日期转换成unix时代。我的Dataframe如下所示：

+----------+-------+
|   Dates  |Reports|
+----------+-------+
|2020-07-20|     34|
|2020-07-21|     86|
|2020-07-22|    129|
|2020-07-23|     98|
+--------+---------+
The output should be 
+----------+-------+
|   Dates  |Reports|
+----------+-------+
|1595203200|     34|
|1595289600|     86|
|1595376000|    129|
|1595462400|     98|
+--------+---------+
``

scala apache-spark apache-spark-sql unix-timestamp

来源：https://stackoverflow.com/questions/63361675/how-to-convert-a-column-of-string-dates-into-a-column-unix-epochs-in-spark

1条答案

按热度按时间

4si2a6ki1#

使用 unix_timestamp .

val df = Seq(("2020-07-20")).toDF("date")
df.show
df.withColumn("unix_time", unix_timestamp('date, "yyyy-MM-dd")).show

+----------+
|      date|
+----------+
|2020-07-20|
+----------+

+----------+----------+
|      date| unix_time|
+----------+----------+
|2020-07-20|1595203200|
+----------+----------+

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如何在spark中将一列字符串日期转换为一列unix epochs

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