hive连接

utugiqy6 于 2021-05-27 发布在 Hadoop

关注(0)|答案(3)|浏览(540)

这就是问题所在：我有一张手术台：

key0    key1    timestamp   partition_key
5   5   2020-03-03 14:42:21.548 1
5   4   2020-03-03 14:40:11.871 1
4   3   2020-03-03 14:43:47.602 2

这个目标表：

key0    key1    timestamp   partition_key
5   4   2020-03-03 13:43:16.695 1
5   5   2020-03-03 13:45:24.793 1
5   2   2020-03-03 13:47:30.668 1
5   1   2020-03-03 13:48:30.669 1
4   3   2020-03-03 13:53:47.602 2
43  3   2020-03-03 14:00:14.016 2

我想得到这个输出：

key0    key1    timestamp   partition_key
5   5   2020-03-03 14:42:21.548 1
5   4   2020-03-03 14:40:11.871 1
5   2   2020-03-03 13:47:30.668 1
5   1   2020-03-03 13:48:30.669 1
4   3   2020-03-03 14:43:47.602 2
43  3   2020-03-03 14:00:14.016 2

在timestamp字段中，我需要key0、key1和partition\u键时最新的记录。另外，我希望目标表中已有记录，但临时表中不存在这些记录
我首先尝试了以下查询：

select 
t1.key0,
t1.key1,
t1.timestamp,
t2.partition_key
from staging_table t2 
left outer join target_table t1 on 
t1.key0=t2.key0 AND
t1.key1=t2.key1 AND
t1.timestamp=t2.timestamp;

sql hadoop Hive Join

来源：https://stackoverflow.com/questions/60511003/hive-join-between-two-tables

3条答案

按热度按时间

cuxqih211#

这看起来像一个优先级排序查询——从暂存中获取所有内容，然后从目标中获取不匹配的行。我要推荐 union all :

select s.*
from staging s
union all
select t.*
from target t left join
     staging s
     on t.key0 = s.key0 and t.key1 = s.key1
where s.key0 is null;

这确实假设暂存具有最新的行—这在示例数据中是正确的。如果不是，我会这样说：

select key0, key1, timestamp, partition_key
from (select st.*,
             row_number() over (partition by key0, key1 order by timestamp desc) as seqnum
      from ((select s.* from source s
            ) union all
            (select t.* from target t
            )
           ) st
     ) st
where seqnum = 1;

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ffscu2ro2#

你需要 FULL JOIN :

select COALESCE(t1.key0, T2.key0) AS key0, COALESCE(t1.key1, T2.KEY1) AS KEY1,
       COALESCE(t1.timestamp, T2.timestamp) AS timestamp, 
       COALESCE(t1.partition_key, t2.partition_key) AS partition_key
t2.partition_key
from staging_table t2 FULL JOIN 
     target_table t1
     on t1.key0 = t2.key0 AND t1.key1 = t2.key1 AND
        t1.timestamp = t2.timestamp;

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blmhpbnm3#

我想你只是想 left join 以及 coalesce() :

select 
    t.key0,
    t.key1,
    coalesce(s.timestamp, t.timestamp) timestamp,
    t.partition_key
from target_table t 
left join  staging_table s 
    on  s.key0 = t2.key0 
    and s.key1 = t.key1 
    and s.partition_key = t.partition_key

对于中的每条记录 target_table ，这将在中搜索记录 staging_table 那是一样的 (key0, key1, partition_key ). 如果有这样的记录，我们就利用它 timestamp 代替 timestamp 从 target_table .

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hive连接

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