我正在做一个项目,需要在scala应用程序中执行一些linux命令(sqoop命令)。请参阅我在vm上尝试使用mysql执行的示例命令。
import sys.process._
"sqoop eval --connect jdbc:mysql://localhost:3306/retail_db --username root --password cloudera --query 'select * from categories'".!
我得到以下错误:
Warning: /usr/lib/sqoop/../accumulo does not exist! Accumulo imports will fail.
Please set $ACCUMULO_HOME to the root of your Accumulo installation.
20/06/24 15:25:27 INFO sqoop.Sqoop: Running Sqoop version: 1.4.6-cdh5.13.0
20/06/24 15:25:27 WARN tool.BaseSqoopTool: Setting your password on the command-line is insecure.
Consider using -P instead.
20/06/24 15:25:27 ERROR tool.BaseSqoopTool: Error parsing arguments for eval:
20/06/24 15:25:27 ERROR tool.BaseSqoopTool: Unrecognized argument: *
20/06/24 15:25:27 ERROR tool.BaseSqoopTool: Unrecognized argument: from
20/06/24 15:25:27 ERROR tool.BaseSqoopTool: Unrecognized argument: categories
我也使用了这个命令,得到了同样的错误信息:
"sqoop eval --connect jdbc:mysql://localhost:3306/retail_db --username root --password cloudera --query 'select * from categories'".!<
有人能帮我找出错误的原因吗。我试过用单引号和双引号,都没有用。我到处找,但找不到任何解决办法。这就是我在这里发帖的原因。注意:在pyspark中成功执行相同的命令,如下所示:
>>> import os
>>> import sys
>>> query = "sqoop eval --connect jdbc:mysql://localhost:3306/retail_db --username root --password
cloudera --query 'select * from categories'"
>>> os.system(query)
Warning: /usr/lib/sqoop/../accumulo does not exist! Accumulo imports will fail.
Please set $ACCUMULO_HOME to the root of your Accumulo installation.
20/06/24 15:28:56 INFO sqoop.Sqoop: Running Sqoop version: 1.4.6-cdh5.13.0
20/06/24 15:28:56 WARN tool.BaseSqoopTool: Setting your password on the command-line is insecure.
Consider using -P instead.
20/06/24 15:28:58 INFO manager.MySQLManager: Preparing to use a MySQL streaming resultset.
----------------------------------------------------
| category_id | category_department_id | category_name |
----------------------------------------------------
| 1 | 2 | Football |
| 2 | 2 | Soccer |
| 3 | 2 | Baseball & Softball |
| 4 | 2 | Basketball |
| 5 | 2 | Lacrosse |
| 6 | 2 | Tennis & Racquet |
1条答案
按热度按时间jdg4fx2g1#
看起来像
sqoop
不认识*
,from
,和categories
作为个人论点。当从命令行调用时,它工作的原因是shell解释引号并将它们表示为单个引号select * from categories
争论。换句话说,shell在将所有内容交给sqoop
程序。这个
.!
方法(即scalaProcessBuilder
)直接启动进程,这意味着命令元素不会传递给shell进行预处理。有两种方法可以解决这个问题。您可以直接调用shell并将命令行作为单个参数传递给它,或者
你可以自己做大部分明显的预处理。
下面是第二个选项的示例。
如您所见,所有单独的参数都作为单独的参数显示,包括最后一个参数。