select * from EMP_TEST order by EMPNO asc;
+------------+-------+----------+------+-------------+------+------+--------+
| EMPNO      | ENAME | JOB      | MGR  | HIREDATE    | SAL  | COMM | DEPTNO |
+------------+-------+----------+------+-------------+------+------+--------+
| 6765423233 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 6767891234 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 6767891236 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 7767891234 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 8767891230 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 8767891233 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 9765423233 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |
| 9767891234 | WARD  | SALESMAN | 7698 | 22-FEB-1981 | 1250 |  500 |     30 |

在我的例子中，如果我参考下面的例子，如何计算分割*
例如：假设：min=0，max=400，no\u of\u mappers=4 split\u size=（400–0）/4=100
所以，拆分：[0100]，[100200]，[200300]，[300400]