我正在尝试使用复杂的数据类型在配置单元中创建一个表。
我的一列是字符串数组,另一列是Map数组。
将数据加载到表中之后,当我尝试查询数据时,在第三列(一个Map数组)中没有得到所需的结果。
以下是我的配置单元查询:
第一步:
create table transactiondb2(order_id int,billtype array<string>,paymenttype array<map<string,int>>)ROW FORMAT
DELIMITED FIELDS TERMINATED BY '\t'
COLLECTION ITEMS TERMINATED BY '|'
MAP KEYS TERMINATED BY '#';
第二步:
load data local inpath '/home/xyz/data.txt' overwrite into table transactiondb2;
第三步:
select * from transactiondb2;
我的输出如下:
好 啊
1 ["A","B"] [{"credit":null,"10":null},{"cash":null,"25":null},{"emi":null,"30":null}]
2 ["C","D"] [{"credit":null,"157":null},{"cash":null,"45":null},{"emi":null,"35":null}]
3 ["X","Y"] [{"credit":null,"25":null},{"cash":null,"38":null},{"emi":null,"50":null}]
4 ["E","F"] [{"credit":null,"89":null},{"cash":null,"105":null},{"emi":null,"85":null}]
5 ["Z","A"] [{"credit":null,"7":null},{"cash":null,"79":null},{"emi":null,"105":null}]
6 ["D","Y"] [{"credit":null,"30":null},{"cash":null,"100":null},{"emi":null,"101":null}]
7 ["A","Z"] [{"credit":null,"50":null},{"cash":null,"9":null},{"emi":null,"85":null}]
8 ["B","Z"] [{"credit":null,"70":null},{"cash":null,"38":null},{"emi":null,"90":null}]
我的输入文件数据如下:
1 A|B credit#10|cash#25|emi#30
2 C|D credit#157|cash#45|emi#35
3 X|Y credit#25|cash#38|emi#50
4 E|F credit#89|cash#105|emi#85
5 Z|A credit#7|cash#79|emi#105
6 D|Y credit#30|cash#100|emi#101
7 A|Z credit#50|cash#9|emi#85
8 B|Z credit#70|cash#38|emi#90
2条答案
按热度按时间ee7vknir1#
我自己解决的。
我们不需要显式地提到一个Map数组,默认情况下,它从一个Map中获取值
e7arh2l62#
创建如下所示的表并加载数据,然后您将得到所需的输出。