如果你能用 SPLIT 功能，这将是非常容易的。例如：

SELECT split(split(t.col, '\\|')[0],'\\:')[1] AS ID,
       split(split(t.col, '\\|')[1], '\\:')[1] AS Value,
       split(split(t.col, '\\|')[2], '\\:')[1] AS Name
FROM (SELECT 'ID(1001):10|Value(1002):8|Name(xyz):7' AS col) t;

+-----+--------+-------+--+
| id  | value  | name  |
+-----+--------+-------+--+
| 10  | 8      | 7     |
+-----+--------+-------+--+

删除括号中的字符串，转换为map并使用map['key']获取字段：

select m['ID'] as id, m['Value'] as value, m['Name'] as Name 
  from (select str_to_map(regexp_replace('ID(1001):10|Value(1002):8|Name(xyz):7','\\(.*?\\)',''),'\\|',':') as m
       )s;

结果：

id      value   name
10      8       7

仅使用regexp:

SELECT regexp_extract(t.col,'(?i)ID.*?:(\\d+)\\|',1)    as ID,
       regexp_extract(t.col,'(?i)Value.*?:(.?+)\\|',1)  as Value,
       regexp_extract(t.col,'(?i)Name.*?:(.?+)\\|*',1)  as Name
FROM (SELECT 'ID(1001):10|Value(1002):8|Name(xyz):7' AS col) t;

结果：

id      value   name
10      8       7