我使用以下flume代理配置从kafka源读取消息并将它们写回hdfs接收器

tier1.sources  = source1
tier 1.channels = channel1
tier1.sinks = sink1

tier1.sources.source1.type = org.apache.flume.source.kafka.KafkaSource
tier1.sources.source1.zookeeperConnect = 192.168.0.100:2181
tier1.sources.source1.topic = test
tier1.sources.source1.groupId = flume
tier1.sources.source1.channels = channel1
tier1.sources.source1.interceptors = i1
tier1.sources.source1.interceptors.i1.type = timestamp
tier1.sources.source1.kafka.consumer.timeout.ms = 100

tier1.channels.channel1.type = org.apache.flume.channel.kafka.KafkaChannel
tier1.channels.channel1.brokerList = 192.168.0.100:9092

tier1.channels.channel1.topic = test
tier1.channels.channel1.zookeeperConnect = 192.168.0.100:2181/kafka
tier1.channels.channel1.parseAsFlumeEvent = false

tier1.sinks.sink1.channel = channel1
tier1.sinks.sink1.type = hdfs
tier1.sinks.sink1.hdfs.writeFormat = Text
tier1.sinks.sink1.hdfs.fileType = DataStream
tier1.sinks.sink1.hdfs.filePrefix = test-kafka
tier1.sinks.sink1.hdfs.fileSufix = .avro
tier1.sinks.sink1.hdfs.useLocalTimeStamp = true
tier1.sinks.sink1.hdfs.path = /tmp/kafka/%y-%m-%d
tier1.sinks.sink1.hdfs.rollCount=0
tier1.sinks.sink1.hdfs.rollSize=0

kafka消息的内容是avro数据，如果每个轮询周期只有一条kafka消息到达，那么它将被正确地序列化到一个文件中。
当两个kafka消息到达同一批时，它们被分组在同一个hdfs文件中，因为avro消息同时包含schema+数据，所以结果文件包含schema+数据+schema+数据，导致它是一个无效的.avro文件。
如何拆分avro事件以将不同的kafka消息拆分为每个消息写入不同的文件
谢谢您