嗨，我得到下面的错误，而运行一个脚本中的java程序，这是正在执行的oozie外壳动作工作流。

Stdoutput 2015-08-25 03:36:02,636  INFO [pool-1-thread-1] (ProcessExecute.java:68) - Exception in thread "main" java.io.IOException: Error opening job jar: /tmp/jars/first.jar
Stdoutput 2015-08-25 03:36:02,636  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at org.apache.hadoop.util.RunJar.main(RunJar.java:124)
Stdoutput 2015-08-25 03:36:02,636  INFO [pool-1-thread-1] (ProcessExecute.java:68) - Caused by: java.io.FileNotFoundException: /tmp/jars/first.jar (No such file or directory)
Stdoutput 2015-08-25 03:36:02,636  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at java.util.zip.ZipFile.open(Native Method)
Stdoutput 2015-08-25 03:36:02,637  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at java.util.zip.ZipFile.<init>(ZipFile.java:215)
Stdoutput 2015-08-25 03:36:02,637  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at java.util.zip.ZipFile.<init>(ZipFile.java:145)
Stdoutput 2015-08-25 03:36:02,637  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at java.util.jar.JarFile.<init>(JarFile.java:154)
Stdoutput 2015-08-25 03:36:02,637  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at java.util.jar.JarFile.<init>(JarFile.java:91)
Stdoutput 2015-08-25 03:36:02,640  INFO [pool-1-thread-1] (ProcessExecute.java:68) -    at org.apache.hadoop.util.RunJar.main(RunJar.java:122)
Exit code of the Shell command 1

以下是文件详细信息：
作业属性：

nameNode=maprfs:///
jobTracker=maprfs:///
queueName=nitin
EXEC=execution.jar
ozie.libpath=${nameNode}/user/oozie/share/lib
oozie.use.system.libpath=true

oozie.wf.application.path=maprfs:/dev/user/oozieTest

工作流.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<workflow-app name="test" xmlns="uri:oozie:workflow:0.4">
    <start to="first" />
    <action name="first">
        <shell xmlns="uri:oozie:shell-action:0.1">
            <job-tracker>${jobTracker}</job-tracker>
            <name-node>${nameNode}</name-node>
            <configuration>
                <property>
                    <name>mapred.job.queue.name</name>
                    <value>${queueName}</value>
                </property>
                </configuration>
            <exec>script</exec>
        <argument>-type mine</argument>
        <argument>-cfg config.cfg</argument>
            <file>script</file>
            <file>${EXEC}#${EXEC}</file>
            <file>config.cfg</file>
            <file>first.jar#first.jar</file>
            <file>second.jar#second.jar</file>
        </shell>
        <ok to="end" />
        <error to="fail" />
    </action>
    <kill name="fail">
        <message>Workflow failed, error message[${wf:errorMessage(wf:lastErrorNode())}]</message>
    </kill>
    <end name="end" />
</workflow-app>

脚本：

# !/bin/bash

# get the user who executed the script

EXECUTING_USER="user1"

# get start time

NOW=$(date +"%T")

# get the host name

HOST="$HOSTNAME"

ARGUMENTSTRING="$@ -user user1 -startTime $NOW"
echo "Passing the following arguments : $ARGUMENTSTRING"

java -cp execution.jar com.hadoop.test.Main "$ARGUMENTSTRING"

exit $?

我从/tmp/jars目录获取execution.jar文件中的first.jar，原因是这个目录不会为oozie工作流用户创建任何权限问题。
任何指导/建议都会很有帮助。
我的问题是：
我想在oozie shell操作节点中执行一个脚本。
从oozie shell操作节点执行的脚本将运行一个java程序
基于参数的java程序将运行first.jar或second.jar