或者在regex中是好的和容易的：只要使用 | . 所以你想要的东西看起来像：

type1|type2

使用regexinterceptor，可以使用或运算符过滤事件，如下所示，

agent.sources.source_3.interceptors.filters.type = regex_filter                                    
 agent.sources.source_3.interceptors.filters.regex = .*type1.*|.*type2.*                    
 agent.sources.source_3.interceptors.filters.excludeEvents = false

顺便说一句，这就是regex在scala/java中的工作原理

图案

scala> import java.util.regex.Pattern;
import java.util.regex.Pattern
scala> import java.util.regex.Matcher;
import java.util.regex.Matcher
scala> val pattern = Pattern.compile(".*type1.*|.*type2.*")
pattern: java.util.regex.Pattern = .*type1.*|.*type2.*

匹配器1

scala> val matcher = pattern.matcher("[20151010][type1][stuff]")
matcher: java.util.regex.Matcher = java.util.regex.Matcher[pattern=.*type1.*|.*type2.* region=0,24 lastmatch=]
scala> val matches = matcher.matches()
matches: Boolean = true

匹配器2

scala> val matcher = pattern.matcher("[20151011][type2][stuff]")
matcher: java.util.regex.Matcher = java.util.regex.Matcher[pattern=.*type1.*|.*type2.* region=0,24 lastmatch=]
scala> val matches = matcher.matches()
matches: Boolean = true

匹配器3

scala> val matcher = pattern.matcher("[20151011][type3][stuff]")
matcher: java.util.regex.Matcher = java.util.regex.Matcher[pattern=.*type1.*|.*type2.* region=0,24 lastmatch=]
scala> val matches = matcher.matches()
matches: Boolean = false

如果你看一下他们的实现代码，他们正在使用 matcher.find() ```
scala> val pattern = Pattern.compile(".type1.|.type2.")
pattern: java.util.regex.Pattern = .type1.|.type2.

scala> val matcher = pattern.matcher("[20151010][type1][stuff]")
matcher: java.util.regex.Matcher = java.util.regex.Matcher[pattern=.type1.|.type2. region=0,24 lastmatch=]

scala> val matches = matcher.find()
matches: Boolean = true