java—如何将两个kafka流连接起来,并在一个具有avro值的主题中生成结果

im9ewurl  于 2021-06-06  发布在  Kafka
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我有两个Kafka的钥匙 String 价值观 Avro 我用ksql创建的格式。
第一个是:

DESCRIBE EXTENDED STREAM_1; 
Type                 : STREAM
Key field            : IDUSER
Timestamp field      : Not set - using <ROWTIME>
Key format           : STRING
Value format         : AVRO
Kafka output topic   : STREAM_1 (partitions: 4, replication: 1)

 Field                      | Type
--------------------------------------------------------
 ROWTIME                    | BIGINT           (system)
 ROWKEY                     | VARCHAR(STRING)  (system)
 FIRSTNAME                  | VARCHAR(STRING)
 LASTNAME                   | VARCHAR(STRING)
 IDUSER                     | VARCHAR(STRING)

第二个是:

DESCRIBE EXTENDED STREAM_2;
Type                 : STREAM
Key field            : IDUSER
Timestamp field      : Not set - using <ROWTIME>
Key format           : STRING
Value format         : AVRO
Kafka output topic   : STREAM_2 (partitions: 4, replication: 1)

 Field                      | Type
--------------------------------------------------------
 ROWTIME                    | BIGINT           (system)
 ROWKEY                     | VARCHAR(STRING)  (system)
 USERNAME                   | VARCHAR(STRING)
 IDUSER                     | VARCHAR(STRING)
 DEVICE                     | VARCHAR(STRING)

所需输出应包括 IDUSER , LASTNAME , DEVICE 以及 USERNAME .
我想 left join 这些溪流 IDUSER )使用streams api并将输出写入kafka主题。
为此,我尝试了以下方法:

public static void main(String[] args) {

    final Properties streamsConfiguration = new Properties();

    streamsConfiguration.put(StreamsConfig.APPLICATION_ID_CONFIG, "kafka-strteams");
    streamsConfiguration.put(StreamsConfig.BOOTSTRAP_SERVERS_CONFIG, "localhost:9092");
    streamsConfiguration.put(StreamsConfig.ZOOKEEPER_CONNECT_CONFIG, "localhost:2181");
    streamsConfiguration.put(AbstractKafkaAvroSerDeConfig.SCHEMA_REGISTRY_URL_CONFIG, "http://localhost:8081");

    streamsConfiguration.put(StreamsConfig.KEY_SERDE_CLASS_CONFIG, Serdes.String().getClass().getName());
    streamsConfiguration.put(StreamsConfig.VALUE_SERDE_CLASS_CONFIG, GenericAvroSerde.class);
    streamsConfiguration.put(ConsumerConfig.AUTO_OFFSET_RESET_CONFIG, "earliest");

    final Serde<String> stringSerde = Serdes.String();
    final Serde<GenericRecord> genericAvroSerde = new GenericAvroSerde();

    boolean isKeySerde = false;
    genericAvroSerde.configure(Collections.singletonMap(AbstractKafkaAvroSerDeConfig.SCHEMA_REGISTRY_URL_CONFIG, "http://localhost:8081"), isKeySerde);

    KStreamBuilder builder = new KStreamBuilder();

    KStream<String, GenericRecord> left = builder.stream("STREAM_1");
    KStream<String, GenericRecord> right = builder.stram("STREAM_2");

    // Java 8+ example, using lambda expressions
    KStream<String, GenericRecord> joined = left.leftJoin(right,
        (leftValue, rightValue) -> "left=" + leftValue + ", right=" + rightValue, /* ValueJoiner */
        JoinWindows.of(TimeUnit.MINUTES.toMillis(5)),
        Joined.with(
          stringSerde, /* key */
          genericAvroSerde,   /* left value */
          genericAvroSerde)  /* right value */
      );
    joined.to(stringSerde, genericAvroSerde, "streams-output-testing");

    KafkaStreams streams = new KafkaStreams(builder, streamsConfiguration);
    streams.cleanUp();
    streams.start();

    Runtime.getRuntime().addShutdownHook(new Thread(streams::close));
}

然而,

KStream<String, GenericRecord> joined = ...

在我的ide上引发错误:

incompatible types: inference variable VR has incompatible bounds

当我尝试使用
String Serde 对于键和值,它都起作用,但数据不是从中可读的 kafka-console-consumer . 我想做的是以avro格式生成数据,以便能够使用 kafka-avro-console-consumer .

k7fdbhmy

k7fdbhmy1#

我的第一个猜测是你正在返回一个 String 而您的代码需要 GenericRecord 结果是:

KStream<String, GenericRecord> joined = left.leftJoin(right,
    (leftValue, rightValue) -> "left=" + leftValue + ", right=" + rightValue, ...)

注意如何 joined 有类型 KStream<String, GenericRecord> ,即值具有类型 GenericRecord ,但联接输出是通过 "left=" + leftValue + ", right=" + rightValue ,具有类型 String .

zfycwa2u

zfycwa2u2#

您可以直接返回值,而不是将值转换为字符串。例如:

KStream joined = left.leftJoin(right,
(leftValue, rightValue) -> { return rightValue});

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