我不明白有没有可能在elasticsearch中根据自定义存储桶的值计算百分位数？例如，我有一个bucket列表：

{"@timestamp": "2019-10-04T17:27:50.228Z", "name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "10", "value": 1}
{"@timestamp": "2019-10-04T17:27:50.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "50", "value": 2}
{"@timestamp": "2019-10-04T17:27:50.228Z", "name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "100", "value": 7}
{"@timestamp": "2019-10-04T17:27:50.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "500", "value": 125}
{"@timestamp": "2019-10-04T17:27:50.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "1000", "value": 1}

{"@timestamp": "2019-10-04T17:28:05.228Z", "name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "10", "value": 0}
{"@timestamp": "2019-10-04T17:28:05.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "50", "value": 1}
{"@timestamp": "2019-10-04T17:28:05.228Z", "name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "100", "value": 3}
{"@timestamp": "2019-10-04T17:28:05.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "500", "value": 134}
{"@timestamp": "2019-10-04T17:28:05.228Z","name": "http_server_requests_histogram","method": "GET","outcome": "SUCCESS","status": "200","uri": "/employee/{id}","le": "1000", "value": 2}

哪里 le 它是一些（请求/函数执行）持续时间和 value 执行的请求数小于或等于某个值（从10ms到1000ms）。根据这些桶，我需要计算百分位。在普罗米修斯，我们可以通过分位数。elasticsearch是否允许使用smth？这是问题的重复，但我没有找到答案。