使用laravel查询生成器的复杂mysql内部连接查询

pgky5nke  于 2021-06-15  发布在  Mysql
关注(0)|答案(1)|浏览(317)

我正在尝试使用laravel查询生成器运行此查询。我认为查询是正确的,因为当我在mysql工作台中运行查询时,查询会执行并得到预期的结果。我知道我们可以用laravel query builder编写原始查询,但它对sql注入漏洞是开放的。所以我试着不带任何疑问地继续。
这是查询

SELECT invoice.InvNo,customer.RouteCode,customer.CustomerCode,rootplan_product.RouteplanCode,invoice.Status 
FROM rootplan_product
INNER JOIN 
customer ON customer.RouteCode = rootplan_product.RouteCode
AND
customer.CustomerCode = rootplan_product.customercode
INNER JOIN
invoice ON invoice.CustomerCode = customer.CustomerCode 
WHERE
rootplan_product.RouteCode='MO-A' AND invoice.Status IN ('PENDING','ACTIVE') 
ORDER BY invoice.Status desc

我把每个表都做成了一个模型,并在控制器中使用。因为表名不同于命名约定。我补充说 protected $table = 'correct_table_name'; 每种型号都有。

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use Illuminate\Support\Facades\DB;
use \App\Route;
use \App\Customer;
use \App\Invoice;
use \App\Rootplan_Product;

这是控制器功能

public function retrieveRouteCodeData(Request $request){
    try {
        $RouteCode = $request->RouteCode;
        $retrievedData = DB::table('rootplan_product')
                    ->join('customer', function($join){
                        $join->on('customer.RouteCode', '=', 'rootplan_product.RouteCode');
                        $join->on(DB::raw('(customer.CustomerCode = rootplan_product.CustomerCode)'));
                    })
                    ->join('invoice', 'invoice.CustomerCode', '=', 'customer.CustomerCode')
                    ->select('invoice.InvNo', 'customer.RouteCode', 'customer.CustomerCode', 'rootplan_product.RouteplanCode', 'invoice.Status')
                    ->where('rootplan_product.RouteCode', $RouteCode)
                    ->orderBy('invoice.Status','desc')
                    ->get();
                    return response()->json(['msg'=>'Updated Successfully', 'result'=>$retrievedData, 'success'=>true]);
      }
      catch (\Exception $e) {
          return response()->json(['msg'=>$e->getMessage()]);

      }

}

在控制台我得到这个错误
“sqlstate[42s22]:找不到列:1054”“on子句”“中的未知列”“(sql:select)” invoice . InvNo , customer . RouteCode , customer . CustomerCode , rootplan_product . RouteplanCode , invoice . Statusrootplan_product 内部连接 customercustomer . RouteCode = rootplan_product . RouteCode 和(customer.customercode=rootplan\u product.customercode)=``内部连接 invoiceinvoice . CustomerCode = customer . CustomerCode 哪里 rootplan_product . RouteCode =mo-a订货人 invoice . Status 描述“
我知道查询是复杂的,任何帮助将不胜感激!

vfh0ocws

vfh0ocws1#

问题出在db::raw语句上。请使用以下选项:

DB::table('rootplan_product')->join('customer', function ($join) {
    $join->on('customer.RouteCode', '=', 'rootplan_product.RouteCode');
    $join->on('customer.CustomerCode', 'rootplan_product.CustomerCode');
})->join('invoice', 'invoice.CustomerCode', '=', 'customer.CustomerCode')
    ->select('invoice.InvNo', 'customer.RouteCode', 'customer.CustomerCode', 'rootplan_product.RouteplanCode', 'invoice.Status')
    ->where('rootplan_product.RouteCode', '123')
    ->whereIn('invoice.Status', ['PENDING','ACTIVE'])
    ->orderBy('invoice.Status', 'desc')
    ->get();

这将生成以下sql:

SELECT `invoice`.`InvNo`,
       `customer`.`RouteCode`,
       `customer`.`CustomerCode`,
       `rootplan_product`.`RouteplanCode`,
       `invoice`.`Status`
FROM `test`
INNER JOIN `customer` ON `customer`.`RouteCode` = `rootplan_product`.`RouteCode`
AND `customer`.`CustomerCode` = `rootplan_product`.`CustomerCode`
INNER JOIN `invoice` ON `invoice`.`CustomerCode` = `customer`.`CustomerCode`
WHERE `rootplan_product`.`RouteCode` = ?
  AND `invoice`.`Status` IN (?, ?)
ORDER BY `invoice`.`Status` DESC

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