如何连接两个具有相同属性的表?

ddrv8njm  于 2021-06-17  发布在  Mysql
关注(0)|答案(3)|浏览(371)

我有两个表,我想用两个表中的数据创建一个具有相同属性的新表。下面是我正在尝试的代码

/* Create a table called NAMES */
CREATE TABLE NAMES(Id integer PRIMARY KEY, Name varchar(100));
CREATE TABLE GAMES(Id integer PRIMARY KEY, Name varchar(100));
CREATE TABLE JJ(Id integer PRIMARY KEY, Name varchar(100));

/* Create few records in this table */
INSERT INTO NAMES VALUES(1,'Tom');
INSERT INTO NAMES VALUES(2,'Lucy');
INSERT INTO NAMES VALUES(3,'Frank');
INSERT INTO NAMES VALUES(4,'Jane');
INSERT INTO NAMES VALUES(5,'Robert');
INSERT INTO GAMES VALUES(7,'Football');
INSERT INTO GAMES VALUES(6,'Rugby');
COMMIT;

/* Display all the records from the table */
SELECT * FROM NAMES;
SELECT * FROM GAMES;
INSERT INTO JJ (Id, Name) VALUES((SELECT * FROM NAMES), (SELECT * FROM GAMES));

SELECT * FROM JJ; 'Error: near line 21: sub-select returns 2 columns - expected 1'
v6ylcynt

v6ylcynt1#

我建议宣布 JJ 作为:

CREATE TABLE JJ (
    Id integer auto_increment PRIMARY KEY,
    Name varchar(100)
);

insert into jj (name)
    select name from names union all
    select game from games;
56lgkhnf

56lgkhnf2#

您尝试合并两个表的方式不太好,因为在b/c中,两个不同的表主键可能相同,这将在第三次插入表时引发错误(重复键)。我更喜欢改变你的表结构,使所有三个表主键自动递增,只按名称而不是id

INSERT INTO JJ ( Name)
select name from (
SELECT name FROM NAMES
union all
SELECT name FROM GAMES
) t
kiz8lqtg

kiz8lqtg3#

这将适用于oracle:

INSERT INTO JJ (Id, Name)((SELECT * FROM NAMES) union all(SELECT * FROM GAMES));

对于mysql:

insert into JJ select * from Names union all select * from Games;

但正如zaynul所说,当两个主键匹配时,它将抛出一个错误!!!!

相关问题