我正在尝试编写一个select查询来在mysql中创建一个视图。视图中的每一行都应该显示从多个表中收集的用户值的每周摘要(sum,avg)。这些表彼此相似,但不完全相同。视图还应该包括行,以防其他表没有该周的值。像这样:
| week_year | sum1 | avg1 | sum2 | user_id |
| --------- | ---- | ---- | ---- | ------- |
| 201840 | | | 3 | 1 |
| 201844 | 45 | 55 | | 1 |
| 201845 | 55 | 65 | | 1 |
| 201849 | 65 | 75 | | 1 |
| 201849 | 75 | 85 | 3 | 2 |
表(简化)如下:
CREATE TABLE IF NOT EXISTS `t1` (
`user_id` INT NOT NULL AUTO_INCREMENT,
`date` DATE NOT NULL,
`value1` int(3) NOT NULL,
`value2` int(3) NOT NULL,
PRIMARY KEY (`user_id`,`date`)
) DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `t2` (
`id` INT NOT NULL AUTO_INCREMENT,
`date` DATE NOT NULL,
`value3` int(3) NOT NULL,
PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `t3` (
`t3_id` INT NOT NULL,
`user_id` INT NOT NULL
) DEFAULT CHARSET=utf8;
我当前的解决方案似乎不合理,我不确定它在数千行的情况下会如何执行:
select ifnull(yearweek(q1.date1), yearweek(q1.date2)) as week_year,
sum(value1) as sum1,
avg(value2) as avg1,
sum(value3) as sum2,
q1.user_id
from (select t2.date as date2,
t1.date as date1,
ifnull(t3.user_id, t1.user_id) as user_id,
t1.value1,
t1.value2,
t2.value3
from t2
join t3 on t3.t3_id=t2.id
left join t1 on yearweek(t1.date) = yearweek(t2.date) and t1.user_id = t3.user_id
union
select t2.date as date2,
t1.date as date1,
ifnull(t3.user_id, t1.user_id) as user_id,
t1.value1,
t1.value2,
t2.value3
from t2
join t3 on t3.t3_id=t2.id
right join t1 on yearweek(t1.date) = yearweek(t2.date) and t1.user_id = t3.user_id) as q1
group by week_year, user_id;
小提琴
当前的解决方案在性能方面还可以吗?还是有更好的选择?如果将来添加第三个(或第四个)表,我将如何管理查询?我应该考虑创建一个单独的表,用触发器更新吗?
提前谢谢。
1条答案
按热度按时间y3bcpkx11#
另一种方法是合并所有数据,然后将其分组。您必须进行性能测试,看看哪一个更好:
希望mysql不会对将null转换为int有异议。。