提前感谢那些花时间研究我的问题的人。我从描述承包商活动的表中获取结果。有大量的真/假字段，我只想显示那些是真的。我创建一个field\u name=>field\u类型的数组，并相应地分析我的显示(抱歉，代码片段太大了。）

$result = $mysqli->query($visitsSQL);
if ( $result->num_rows == 0 ){ // Visit records don't exist
    $_SESSION['message'] = "Cannot find any unpaid visits";
    header("location: error.php");
}
else { // unpaid visits exist
    $fields= array();
    while ($finfo = mysqli_fetch_field($result)){
    $fields [$finfo->name]= $finfo->type ; //this array holds field names -> field types    
    }  //finish fetching keys and types
    echo "<br>";
    echo "<br>Begin visit records<br>";
    echo "<div class='review_row'> </div>"; //this puts a thin line to separate visits

    while ($visit = $result->fetch_assoc()) {  //here's where each visit is compiled and sent to screen

        echo "<div class='review_row'>";  //this puts a thin line on the bottom to separate visits

     foreach ($fields as $k => $v) { 

        $field_name = $k;
        $field_type = $v;
        $field_data = $visit[$field_name];

        switch ($field_type) {

            case 1:   //The field is a True / False field
                if ($field_data ==1){  //show the field only if the value is set to True
                   echo "I am a YES/NO field called " . $field_name . " <br>";  //This line is a test 
                   echo "<span style='color: #009999;> - " . $field_name . "</span><br>";              
                }
                break;
            case 4:  //The field is a double numeric
                   if ($field_data != null) {       //show the field only if the value is set to True             
                echo "<span style='color: #b38f00';>" . $field_name . "</span>  " . $field_data . "<br>";  
                   }
                break;
            case 253: //A text field
                   if ($field_data != null) {                    
                echo "<span style='color: #b38f00';>" . $field_name . "</span>  " . $field_data . "<br>";  
                   }
                break;
            case 254: //a Datetime field
                   if ($field_data != null) {                    
                echo "<span style='color: #b38f00';>" . $field_name . "</span>  " . $field_data . "<br>";  
                   }
                break;
            default: { //field type is not represented above
              // do nothing so far  I take care of each field type above 
            }             
        }  //end of switch
    }  //end of foreach 
}  //end of while loop for the query results
echo "</div>";

}//确定是否有要显示的记录的if/else的结尾
奇怪的结果出现在“switch”语句中，其中“case1”。我当前的测试记录有7个yes/no字段，它们的值都设置为1。他们是
准备好的晚餐
清理晚餐的盘子
购买杂货
洗好的和叠好的衣服
水洗床上用品
真空地毯
清扫厨房地板
我应该为每个“field_type=1”得到两个“echo”：（1）我的测试echo和（2）我最终想要显示的内容，但由于某些原因，它们交替显示-见下图。我已经为此奋斗了两天，尝试if/then解析，但是我得到了这种“每秒钟一次”类型的结果。 screenshot of output from query 谢谢你的建议和指导。