laravel多记录查询

e3bfsja2 于 2021-06-18 发布在 Mysql

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|  id  | name           | email                                       | provider    | created_at
---------------------------------------------------------------------------------------
 | 1 | Mr Smith        | mr.smith@example.com         | facebook | 2018-11-01 09:00:00 | 
 | 2 | Mrs Smith      | mrs.smith@example.com      | facebook  | 2018-11-01 09:00:00 | 
 | 3 | Miss Smith     | miss.smith@example.com    | email        | 2018-11-01 09:00:00 | 
 | 4 | Doctor Smith | doctor.smith@example.com | email        | 2018-11-01 09:00:00 | 
 | 5 | Lord Smith    | lord.smith@example.com      | twitter      | 2018-11-01 09:00:00 | 
 | 6 | Lady Smith    | lady.smith@example.com      | email        | 2018-11-01 09:00:00 | 
 | 7 | Mr Smith        | mr.smith@example.com         | facebook | 2018-11-02 09:00:00 | 
 | 8 | Mrs Smith      | mrs.smith@example.com       | facebook  | 2018-11-02 09:00:00 | 
 | 9 | Doctor Smith | doctor.smith@example.com  | email        | 2018-11-02 09:00:00 | 
 | 10 | Lord Smith   | lord.smith@example.com       | twitter      | 2018-11-02 09:00:00 | 
 | 11 | Lady Smith   | lady.smith@example.com      | email        | 2018-11-02 09:00:00 | 
 | 12 | Mr Smith      | mr.smith@example.com         | facebook | 2018-11-03 09:00:00 | 
 | 13 | Mrs Smith    | mrs.smith@example.com       | facebook | 2018-11-03 09:00:00 | 
 | 14 | Miss Smith   | miss.smith@example.com     | email        | 2018-11-03 09:00:00 | 
 | 15 | Lord Smith   | ord.smith@example.com       | twitter      | 2018-11-03 09:00:00 | 
 | 16 | Lady Smith  | lady.smith@example.com      | email        | 2018-11-03 09:00:00 |

查询的客户条件示例：
访问次数超过2次的客户
客户首次访问是在2天前
客户上次访问是在1天前
客户提供商是facebook
当前查询：

$Customers = Customer::groupBy('email')
                 ->havingRaw('COUNT(*) > 2’)
                 ->where('created_at', '<', Carbon::now()->subDays(2)->toDateTimeString())
                 ->get();

我不知道如何拉第一个客户记录检查它是否超过2天，然后拉最后一个记录，并确保它超过1天。我知道我当前的查询对于我想要实现的目标来说是完全无用的，但是我再一次努力地把它拉到一起。
预期结果：

|  id  | name           | email                                       | provider    | created_at
---------------------------------------------------------------------------------------
 | 12 | Mr Smith      | mr.smith@example.com         | facebook | 2018-11-03 09:00:00 | 
 | 13 | Mrs Smith    | mrs.smith@example.com       | facebook | 2018-11-03 09:00:00 |

mysql php laravel eloquent

来源：https://stackoverflow.com/questions/53137551/laravel-eloquent-query-multiple-records-based-on-set-criteria

2条答案

按热度按时间

jv4diomz1#

用mysql方言进行选择的sql查询如下

SELECT id, name, email, provider, created_at
FROM customers 
WHERE provider = 'facebook'
GROUP BY email
HAVING 
  count(*) > 2
  AND min(created_at) < date_sub(now(), interval 2 day)
  AND max(created_at) < date_sub(now(), interval 1 day)

可以翻译成这样一个雄辩的问题

$havingClause = 'count(*) > ? AND min(created_at) < ? AND max(created_at) < ?';
$havingClauseBindings = [
   2,
   Carbon::now()->subDays(2)->toDateTimeString(),
   Carbon::now()->subDays(1)->toDateTimeString()
];
$customers = Customer::where('provider', 'facebook')
                       ->groupBy('email')
                       ->havingRaw($havingClause, $havingClauseBindings)
                       ->get();

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vhipe2zx2#

您要查找的查询是：

select * from customers group by email having count(*) > 2 and min(created_at) <= '2018-10-02 09:00:00' and max(created_at) <= '2018-10-03 09:00:00' and provider = 'facebook'

假设当前时间为2018-10-04 09:00:00。
雄辩地说：

$Customers = Customer::groupBy('email')
             ->havingRaw('COUNT(*) > 2')
             ->havingRaw('max(created_at) < ?' , [Carbon::now()->subDays(2)->toDateTimeString()])
             ->havingRaw('min(created_at) < ?' , [Carbon::now()->subDays(1)->toDateTimeString()])
             ->havingRaw('provider = ?' , ['facebook'])
             ->get();

另一方面，使用雄辩的方法可以链接方法，如下所示

$customers = Customer::groupBy('email');

if( $includeCount ) {

     $customers->havingRaw('COUNT(*) > 2');
}
...
...
...

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laravel多记录查询

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