首先,我不熟悉spring框架和hibernate。请容忍我。
我正在尝试实现一个搜索过滤器,用户可以选择指定名字、姓氏、出生日期、性别、国家、语言等 Guest
它存储这些记录。一些列(如gender、country和language)存储在具有唯一主键的单独表中。也就是说,我把这些记录的外键存储在 Guest
table。
搜索的所有字段都是可选的。对于每个缺少的搜索字段,程序都必须假定为“any”。
考虑到这一点,我可以 LIKE
以及字符串列的通配符,例如名字和姓氏。对于外键列,我使用 =
接线员。如果缺少搜索字段,则该字段将替换为 null
.
当我只指定名字(或者姓)时,我无法在输出中得到任何东西。
这是密码 CrudRepository
我写的接口。
public interface GuestRepository extends CrudRepository<Guest, Integer> {
@Query("SELECT guest FROM Guest guest WHERE guest.propertyIdentifier = ?1 AND guest.firstName LIKE %?2% AND guest.lastName LIKE %?3% AND guest.titleIdentifier = ?4 AND guest.dateOfBirth = ?5 AND guest.genderIdentifier = ?6 AND guest.countryIdentifier = ?7 AND guest.languageIdentifier = ?8 AND guest.passport LIKE %?9%")
Iterable<Guest> findGuests(Integer propertyIdentifier, String firstName, String lastName, Integer titleIdentifier, Date dateOfBirth, Integer genderIdentifier, Integer countryIdentifier, Integer languageIdentifier, String passport);
}
这是你的答案 Guest
实体。
@Entity
public class Guest {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer identifier;
private Integer propertyIdentifier;
private String firstName;
private String lastName;
private Integer titleIdentifier;
@Temporal(TemporalType.DATE)
private Date dateOfBirth;
private Integer genderIdentifier;
private Integer countryIdentifier;
private Integer languageIdentifier;
private String passport;
private Integer status;
public Integer getIdentifier() {
return identifier;
}
public void setIdentifier(Integer identifier) {
this.identifier = identifier;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public Date getDateOfBirth() {
return dateOfBirth;
}
public void setDateOfBirth(Date dateOfBirth) {
this.dateOfBirth = dateOfBirth;
}
public String getPassport() {
return passport;
}
public void setPassport(String passport) {
this.passport = passport;
}
public Integer getLanguageIdentifier() {
return languageIdentifier;
}
public void setLanguageIdentifier(Integer languageIdentifier) {
this.languageIdentifier = languageIdentifier;
}
public Integer getCountryIdentifier() {
return countryIdentifier;
}
public void setCountryIdentifier(Integer countryIdentifier) {
this.countryIdentifier = countryIdentifier;
}
public Integer getGenderIdentifier() {
return genderIdentifier;
}
public void setGenderIdentifier(Integer genderIdentifier) {
this.genderIdentifier = genderIdentifier;
}
public Integer getTitleIdentifier() {
return titleIdentifier;
}
public void setTitleIdentifier(Integer titleIdentifier) {
this.titleIdentifier = titleIdentifier;
}
public Integer getStatus() {
return status;
}
public void setStatus(Integer status) {
this.status = status;
}
public Integer getPropertyIdentifier() {
return propertyIdentifier;
}
public void setPropertyIdentifier(Integer propertyIdentifier) {
this.propertyIdentifier = propertyIdentifier;
}
}
如果用户没有为搜索字段指定值,如何实现假定为“any”的搜索筛选器?我还有别的选择吗?
1条答案
按热度按时间ilmyapht1#
考虑使用标准api。它看起来像这样:
其中searchedguest是具有可选填充字段的对象。