我正试图用python编写一个mysql查询,但在执行它时,总是出现语法错误#1064(42000)。已获取数据,但该错误阻止查询完成。
mysql.connector.errors.ProgrammingError: 1064
(42000): You have an error in your SQL syntax; check
the manual that corresponds to your MySQL server
version for the right syntax to use near '1
'(data in address_line_1)' NULL '(data in city field)'
'(data in postal code field)' '(data in state code field)' 'US'
(latitude data) (longitude data) '(first two characters of is_active field data)' at line 1
它或多或少告诉我错误在哪里,但不是什么原因造成的。我想我可能在正确引用查询字符串中的某些内容时遇到了问题。我不知道错误是什么,因为对我来说,查询似乎是正确的,而且我不知道python-mysql能够诊断格式错误的所有特性。
下面是表创建命令(在花了几个小时调整之后,这个命令有效):
sql=("CREATE TABLE IF NOT EXISTS `locations` ("
" `id` BIGINT NOT NULL AUTO_INCREMENT PRIMARY KEY,"
" `location_id` VARCHAR(48),"
" `is_valid` BOOLEAN,"
" `street_line_1` VARCHAR(48),"
" `street_line_2` VARCHAR(48),"
" `city` VARCHAR(16),"
" `postal_code` VARCHAR(8),"
" `state_code` CHAR(2),"
" `country_code` CHAR(2),"
" `latitude` DECIMAL(10,6),"
" `longitude` DECIMAL(10,6),"
" `accuracy` VARCHAR(12),"
" `is_active` BOOLEAN,"
" `is_commercial` BOOLEAN,"
" `is_forwarder` BOOLEAN,"
" `delivery_point` VARCHAR(18),"
" `last_sale_date` DATE,"
" `total_value` INT(12)"
") ENGINE = InnoDB")
有17个字段不是自动递增的id键。下面是实际的insert查询:
sql = ("INSERT INTO `locations`(`location_id`, `is_valid`, `street_line_1`,"
" `street_line_2`, `city`, `postal_code`, `state_code`, `country_code`,"
" `latitude`, `longitude`, `accuracy`, `is_active`, `is_commercial`,"
" `is_forwarder`, `delivery_point`, `last_sale_date`, `total_value`)"
" VALUES(%s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s)")
我错过了什么?谢谢你的帮助。
2条答案
按热度按时间cedebl8k1#
第一个建议是用逗号分隔%s
hgc7kmma2#
我猜您的值不包括“,”,因此值(%s%s…)不正确。您需要改用值(%s,%s,…)。