错误1054(42s22)：“where子句”中的未知列“year”

cbjzeqam 于 2021-06-03 发布在 Mysql

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不知道我的列名是怎么回事。

mysql> SELECT fullname FROM country WHERE year-independence > 1945;
ERROR 1054 (42S22): Unknown column 'year' in 'where clause'

以下是表格限制5：

+----------------------------------------------+
| code | fullname             | continent     | region                    | area   | year-independence | population | avg-lifespan | avg-GNP   | form-government                              |
+------+----------------------+---------------+---------------------------+--------+-------------------+------------+--------------+-----------+----------------------------------------------+
| ABW  | Aruba                | North America | Caribbean                 |    193 |                 0 |     103000 |        78.40 |    828.00 | Nonmetropolitan Territory of The Netherlands |
| AFG  | Afghanistan          | Asia          | Southern and Central Asia | 652090 |              1919 |   22720000 |        45.90 |   5976.00 | Islamic Emirate                              |
| AGO  | Angola               | Africa        | Central Africa            | 124670 |              1975 |   12878000 |        38.30 |   6648.00 | Republic                                     |
| AIA  | Anguilla             | North America | Caribbean                 |     96 |                 0 |       8000 |        76.10 |     63.20 | Dependent Territory of the UK                |
| ALB  | Albania              | Europe        | Southern Europe           |  28748 |              1912 |    3401200 |        71.60 |   3205.00 | Republic

sql mysql mysql-error-1054

来源：https://stackoverflow.com/questions/52788553/error-1054-42s22-unknown-column-year-in-where-clause

2条答案

按热度按时间

pkmbmrz71#

尝试：

SELECT fullname FROM country WHERE `year-independence` > 1945;

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vxbzzdmp2#

mysql中的某些对象，包括数据库、表、索引、列、别名、视图、存储过程、分区、表空间、资源组和其他对象名，称为标识符。[…]如果标识符包含特殊字符或是保留字，则每次引用时都必须引用它。[…]
根据https://dev.mysql.com/doc/refman/8.0/en/identifiers.html
标识符引号字符是反勾号（`）：

mysql> SELECT * FROM `select` WHERE `select`.id > 100;

对你来说

mysql> SELECT `fullname` FROM `country` WHERE `year-independence` > 1945;

你可能已经注意到我用反记号包围了所有的标识符，因为这样做是一个好习惯。

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错误1054(42s22)：“where子句”中的未知列“year”

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