我怎样才能做左连接 null
在雄辩的查询生成器中?
我有两种型号: Customer
( customers
表)和 Appointment
( appointments
表)。客户可以有0个或多个约会。客户和约会都可以软删除。
我想在查询生成器中复制此查询:
查询1:
SELECT max(a.date) AS max_date, c.* FROM customers AS c
LEFT JOIN appointments AS a ON a.customer_id = c.id AND a.deleted_at IS NULL
WHERE c.deleted_at IS NULL
GROUP BY c.id;
我知道:
Customer::selectRaw('max(appointments.date) as max_date, customers.*')
->leftJoin('appointments', 'appointments.customer_id', '=', 'customers.id')
->where('appointments.deleted_at')
->groupBy('customers.id');
结果如下:
问题2:
SELECT max(a.date) AS max_date, c.* FROM customers AS c
LEFT JOIN appointments AS a ON a.customer_id = c.id
WHERE c.deleted_at IS NULL AND a.deleted_at IS NULL
GROUP BY c.id;
但是查询1和查询2之间有一点不同:
查询1包括所有约会都被软删除的客户(这就是我想要的)。查询2不存在。
有没有一种方法可以雄辩地做到这一点,而不诉诸子查询?这个查询的输出转到每页有100条(或更多)记录的“index”视图,所以我不想不必要地减慢它的速度。我还希望用户能够排序的最大日期的结果。
我唯一合理的选择是简单的“原始sql查询”吗?
1条答案
按热度按时间pgky5nke1#
leftJoin()
接受结束: