我正在尝试将android应用程序中的一行插入mysql数据库,通过localhost在xampp服务器上运行。我的数据库连接是正确的,php文件的路径也是正确的。但我无法将应用程序中的数据上传到mysql。
下面是我的代码:
insertactivity.java文件:
public class InsertActivity extends AppCompatActivity {
EditText eid,ename,eprice,equantity,esupemail,esupphone;
Button addbtn;
ProgressDialog progressDialog;
String newname,newprice,newqnty,newem,newno;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_insert);
eid=findViewById(R.id.ETid);
ename=findViewById(R.id.ETname);
eprice=findViewById(R.id.ETprice);
equantity=findViewById(R.id.ETquantity);
esupemail=findViewById(R.id.ETsupemail);
esupphone=findViewById(R.id.ETsupphone);
addbtn=findViewById(R.id.addnewbtn);
progressDialog = new ProgressDialog(InsertActivity.this);
addbtn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
progressDialog.setMessage("Please Wait, We are Inserting Your
Data on Server");
progressDialog.show();
GetValueFromEditText();
// Creating string request with post method.
StringRequest stringRequest = new
StringRequest(Request.Method.POST, Url.Insert_URL,
new Response.Listener<String>() {
@Override
public void onResponse(String ServerResponse) {
Log.i("tag",ServerResponse);
// Hiding the progress dialog after all task
complete.
progressDialog.dismiss();
try {
JSONObject jsonObject = new
JSONObject(ServerResponse);
Toast.makeText(getApplicationContext(),
jsonObject.getString("message"),
Toast.LENGTH_LONG).show();
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
// Hiding the progress dialog after all task
complete.
progressDialog.dismiss();
// Showing error message if something goes
wrong.
Toast.makeText(InsertActivity.this,
volleyError.toString(),
Toast.LENGTH_LONG).show();
}
}) {
@Override
protected Map<String, String> getParams() {
// Creating Map String Params.
Map<String, String> params = new HashMap<String, String>
();
// Adding All values to Params.
params.put("ename", newname);
params.put("eprice", newprice);
params.put("equantity", newqnty);
params.put("esupemail", newem);
params.put("esupphone", newno);
return params;
}
};
// Creating RequestQueue.
RequestQueue requestQueue =
Volley.newRequestQueue(InsertActivity.this);
// Adding the StringRequest object into requestQueue.
requestQueue.add(stringRequest);
}
});
}
// Creating method to get value from EditText.
public void GetValueFromEditText(){
newname = ename.getText().toString().trim();
newprice = eprice.getText().toString().trim();
newqnty = equantity.getText().toString().trim();
newem = esupemail.getText().toString().trim();
newno = esupphone.getText().toString().trim();
}
}
这是我用来插入数据的php文件:
<?php
include ("dbconnect.php");
$response = array();
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$name = $_POST['ename'];
$price = $_POST['eprice'];
$qnty = $_POST['equantity'];
$email = $_POST['esupemail'];
$phone = $_POST['esupphone'];
$adding = "INSERT INTO
information(ID,Name,Price,Quantity,
Supplier,Sup_Phone,Stockin,Stockout) VALUES(NULL,'$name','$price',
'$qnty','$email','$phone',NULL,NULL)";
$result = mysqli_query($dbconnect,$adding);
if($result>0)
{
$response['error'] = false;
$response['message']="ADDED Successfully"
}
else{
$response['error'] = true;
$response['message']="Error in Inserting"
}
}
?>
暂无答案!
目前还没有任何答案,快来回答吧!