节点代码如下：

app.get('/search', function(req, res){
    var keyword = req.query.q;
    con.query("SELECT Post_Title, Post_Icon, Post_Cont, Post_Author, Post_Date FROM Posts WHERE Post_Title LIKE '" + keyword + "' OR Post_Icon LIKE '" + keyword + "' OR Post_Cont LIKE '" + keyword + "' OR Post_Author LIKE '" + keyword + "' OR Post_Date LIKE '" + keyword + "' ORDER BY Post_Date ASC", function (err, result) {
    if (err){
    console.log("Error on DB SELECT.");
    console.log(err);
    tellSelectError(req, res);
}else{
    console.log("Database selected");
    console.log(result);
    /*res.render('index', {
        info: info,
        result: result
    });*/
    res.json(result);
    }
});
});

它将空的json发送到客户端浏览器。
截图上传地点：https://i.stack.imgur.com/kpsda.jpg
请帮忙。。。。。此代码正在工作： SELECT * FROM Posts WHERE Post_ID = " + keyword 但是我想用like来处理所有不包括post\u id的文章。
控制台日志（err）；没有记录错误。
有个消息：当我把sql改为 SELECT * FROM Posts ，它正确地返回所有原始值，但 SELECT Post_Title, Post_Icon, Post_Cont, Post_Author, Post_Date FROM Posts WHERE Post_Title LIKE '" + keyword + "' OR Post_Icon LIKE '" + keyword + "' OR Post_Cont LIKE '" + keyword + "' OR Post_Author LIKE '" + keyword + "' OR Post_Date LIKE '" + keyword + "' ORDER BY Post_Date ASC 未按预期工作。