我在mariadb 10.2.7中使用xampp,我安装了一个seo模块,然后使用json,它显示了以下错误。
Error: Uncaught Exception: Error: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'rows' at line 1<br />Error No: 1064<br />SELECT FOUND_ROWS() as rows in C:\xampp\htdocs\store\system\library\db\mysqli.php:40
1条答案
按热度按时间mwg9r5ms1#
类modeltoolseopackageeditor扩展模型{
公共函数uu构造($registry){父函数::u构造($registry);
}
/为datatables行创建数据输出数组@param array$columns column information array@param array$data data来自sql get*@return array formatted data in a row-based format*/public function data_output($columns,$data,$type=''){$out=array();
公共函数pick_fields($a,$prop){$out=array();
}