这个问题在这里已经有了答案:
外键未填充主键值(1个答案)
两年前关门了。
自动递增似乎工作得很好,但它似乎有一些东西与主键或外键(也许?)我不知道,因为我没有得到任何错误消息。以下是我的数据库代码:
DROP TABLE IF EXISTS `Album`;
CREATE TABLE `Album` (
`id` int NOT NULL AUTO_INCREMENT,
`album_name` varchar(100) NOT NULL,
`album_thumbnail` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Album` (`album_name`,`album_thumbnail`)
VALUES
('est','/media/test.jpg'),
('consequatur','/media/test.jpg'),
('cumque','/media/test.jpg'),
('sunt','/media/test.jpg'),
('maiores','/media/test.jpg'),
('enim','/media/test.jpg'),
('voluptatibus','/media/test.jpg'),
('officiis','/media/test.jpg'),
('sapiente','/media/test.jpg'),
('itaque','/media/test.jpg');
DROP TABLE IF EXISTS `Artist`;
CREATE TABLE `Artist` (
`id` int NOT NULL AUTO_INCREMENT,
`artist_name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Artist` (`artist_name`)
VALUES
('Dr. Liza Gleason'),
('Luz Feest'),
('Nigel Beier'),
('Dan Mosciski DDS'),
('Reta Altenwerth'),
('Felipe Runolfsson'),
('Pamela Kessler'),
('Mr. Chester Von PhD'),
('Nayeli Rosenbaum IV'),
('Haven Roberts');
DROP TABLE IF EXISTS `Track`;
CREATE TABLE `Track` (
`id` int NOT NULL AUTO_INCREMENT,
`track_name` varchar(100) NOT NULL,
`time` time DEFAULT NULL,
`likes` int(9) unsigned NOT NULL,
`track_link` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Track` (`track_name`,`time`,`likes`,`track_link`)
VALUES
('facere','07:29:26','0','http://heaney.com/'),
('placeat','13:31:39','0','http://mclaughlinschowalter.com/'),
('numquam','11:51:06','0','http://www.reicherthowell.com/'),
('accusantium','13:58:47','0','http://www.white.net/'),
('molestiae','14:22:06','0','http://www.leuschke.info/'),
('dolores','05:33:34','0','http://www.schuppe.com/'),
('natus','18:14:07','0','http://klocko.com/'),
('optio','01:44:57','0','http://hillshoeger.biz/'),
('laudantium','23:41:02','0','http://hartmannmiller.org/'),
('illo','05:18:46','0','http://www.sanford.com/');
DROP TABLE IF EXISTS `Album_Track`;
CREATE TABLE `Album_Track` (
`album_id` int NOT NULL,
`track_id` int NOT NULL,
FOREIGN KEY (`album_id`) REFERENCES `Album`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE,
FOREIGN KEY (`track_id`) REFERENCES `Track`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
DROP TABLE IF EXISTS `Artist_Album`;
CREATE TABLE `Artist_Album` (
`artist_id` int NOT NULL,
`album_id` int NOT NULL,
FOREIGN KEY (`artist_id`) REFERENCES `Artist` (`id`) ON DELETE RESTRICT ON UPDATE CASCADE,
FOREIGN KEY (`album_id`) REFERENCES `Album` (`id`) ON DELETE RESTRICT ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
我得到了所有的表值,除了专辑和艺术家专辑。它们保持空白,没有任何错误。我真的很感激任何帮助。
1条答案
按热度按时间6vl6ewon1#
嗯,在table上
Album_Track
列album_id
以及track_id
没有任何默认值。如果不指定,则INSERT
查询失败。您需要指定这些列的值,因为mysql没有任何猜测它们的方法。它怎么能猜出来?
必须有错误代码或错误消息。因为某些原因,你没有看到他们。
正确的插入方式是,例如:
这将正确插入一行。