伙计们,你们能帮我建立一个合适的mysql select与以下这些选择的连接吗?
我的选择如下所示:
SELECT budget as budget from projects where id =96
SELECT sum(value) as expenses from expenses where project_id =96
SELECT sum(estimated_hours * t2.man_hour) as estimated from project_has_tasks t1 left join
users t2 on t1.user_id = t2.id where project_id =96
SELECT sum(TIME_FORMAT(SEC_TO_TIME (time_spent),'%k.%i' )
* t2.man_hour) as time_spent_cost FROM project_has_tasks t1
left join users t2 on t1.user_id = t2.id where t1.project_id ='96'
他们工作正常,但我想达到一个结果,如:
| budget | expenses | estimated | time_spent_cost |
____________________________________________________
| 298833 | 24234 | 4434333 | 343434 |
无论如何,我刚刚建立了一个公共选择,但它不能正常工作(不正确的总和…)
SELECT t1.project_id, t3.budget,
IFNULL(sum(t4.value),0) as additional_costs,
IFNULL(sum(estimated_hours)* t2.man_hour ,0)
as estimated_hours_costs,
IFNULL(TIME_FORMAT(SEC_TO_TIME
(sum(t1.time_spent)),'%k.%i' )* t2.man_hour,0)
as time_spent_cost, NOW()
FROM project_has_tasks t1 left join
users t2 on t1.user_id = t2.id left join
projects t3 on t1.project_id = t3.id
left join expenses t4
on t1.project_id = t4.project_id
WHERE t1.project_id ='96' group by t1.project_id
谢谢你的帮助。
1条答案
按热度按时间knsnq2tg1#
当然总和太高了,我假设费用和用户都返回多行,并且总和是在所有行上计算的,因此如果有三个用户,那么估计值将是您想要的值的三倍。假设项目只返回一行,这可能会更好: