我有使用此sql的重复记录:
SELECT emp.id, first_name, second_name, last_name, department, positions,
GROUP_CONCAT(email, " ", email_type SEPARATOR " || ") AS mails,
GROUP_CONCAT(number, " ", number_type SEPARATOR " || ") AS numbers
FROM geography.employee AS emp
INNER JOIN geography.employee_email AS ee ON emp.id = ee.email_FK
LEFT JOIN geography.employee_number AS en ON emp.id = en.number_FK
WHERE first_name = 'John' AND last_name = 'Ausini'
GROUP BY emp.id
所以我得到这些邮件的结果:
heyhey@abv.bg personal || heyhey@abv.bg personal || summer_geals@bwtc.co work || summer_geals@bwtc.co work || ivanov@abv.bg personal || ivanov@abv.bg personal
对于数字:
+7654656656565 work || +7654656465655 personal || +7654656656565 work || +7654656465655 personal || +7654656656565 work || +7654656465655 personal
奇怪的是,在我的第二份记录中,邮件不是重复的,邮件:
hei@abv.bg personal || hurei@abv.bg personal || burei@abv.bg personal || work@bwtc.com work
……但在这张唱片里,我没有数字,也许这张唱片把它从最上面的那张中去掉了。我的预期输出不是每个记录重复数据(对于第一个记录示例):
heyhey@abv.bg personal || summer_geals@bwtc.co work || ivanov@abv.bg personal
…数字也没有重复。distinct也不起作用(如果我把它放在select之后),我尝试过它,尽管我不喜欢掩盖问题。
我在表格中的数据:
2条答案
按热度按时间9jyewag01#
因为你只得到一个用户的信息,我同意萨尔曼a的回答;但是如果你是针对多个(或所有)用户,而用户往往有很多电子邮件和号码,这个版本可能会更快。
ntjbwcob2#
mysql数据库
GROUP_CONCAT
允许您指定DISTINCT
在连接之前应该消除重复项: