这是我的密码：

<?= $this->Form->create('Posts', array('url' => array('controller' => 'MyController', 'action' => 'index')));?>
                        <?= $this->Form->input('title', array('type'=>'title','class'=>'form-control mr-sm-2'));?>
                        <?= $this->Form->textarea('text', array('type'=>'text','rows' => '3','class'=>'form-control'));?>
                        <?= $this->Form->submit('Posten', array('class'=>'btn btn-outline-success my-2 my-sm-0','style'=>'float:right'));?>
                    <?= $this->Form->end();?>

这是我的控制器：

$post = $this->Posts->newEntity();
    if ($this->request->is('post')) {
        $post = $this->Posts->patchEntity($post, $this->request->getData());
        debug($post);
        if ($this->Posts->save($post)) {

        $this->Flash->success(__('You have posted something.'));
        }

        return $this->redirect(['action' => 'index']);
    }else {
        $this->Flash->error(__('Error, plase check your'));
    }

问题在于：

INSERT INTO posts (title, text) VALUES (:c0, :c1);

但我需要：

INSERT INTO posts (title, text,user_id,picture_id) VALUES (a,b,$user_id,$picture_id);

问题是我需要将它插入控制器而不是视图中。有人能帮我吗？