我需要用Pig拉丁形式写一个句子，我几乎成功了，除了一个案例，我几乎放弃了例如：如果我的单词以a\e\o\u\i开头，这个单词看起来会像easy->easyway，apple->appleway
如果不是以我在上面写的一封信开头，它看起来会是这样的：box->oxbay，king->ingkay
粗体部分我成功了，但在第一部分开头有一个字母e\o\u\i，我不知道把w放在哪里，需要一些帮助
这是我的密码，提前谢谢

# include <iostream>

//Since those are used in ALL function of program, it wont hurt to set it to global
//Else it is considered EVIL to declare global variables
const int maxLine = 100;
char phraseLine[maxLine] = { '\0' };

void pigLatinString();

using namespace std;

void main()
{
    // Displayed heading of program

    cout << "* You will be prompted to enter a string of *" << endl;
    cout << "* words. The string will be converted into  *" << endl;
    cout << "* Pig Latin and the results displayed.      *" << endl;
    cout << "* Enter as many strings as you would like.  *" << endl;

    //prompt the user for a group of words or press enter to quit
    cout << "Please enter a word or group of words. (Press enter to quit)\n";
    cin.getline(phraseLine, 100, '\n');
    cout << endl;

    // This is the main loop. Continue executing until the user hits 'enter' to quit.
    while (phraseLine[0] != '\0')
    {

        // Display the word (s) entered by the user
        cout << "You entered the following: " << phraseLine << endl;

        // Display the word (s) in Pig Latin
        cout << "The same phrase in Pig latin is: ";
        pigLatinString();
        cout << endl;

        //prompt the user for a group of words or press enter to quit
        cout << "Please enter a word or group of words. (Press enter to quit)\n";
        cin.getline(phraseLine, 100, '\n');
    }
    return;
}

void pigLatinString() //phraseLine is a cstring for the word,  maxline is max length of line
{ //variable declarations
    char tempConsonant[10];
    tempConsonant[0] = '\0';
    int numberOfConsonants = 0;
    char previousCharacter = ' ';
    char currentCharacter = ' ';
    bool isInWord = 0;

    // for loop checking each index to the end of whatever is typed in
    for (int i = 0; i < maxLine; i++)
    {

        //checking for the end of the phraseline 
        if (phraseLine[i] == '\0')
        {//checking to see if it's in the word
            if (isInWord)
            {//checking to see that there wasn't a space ahead of the word and then sending the cstring + ay to the console
                if (previousCharacter != ' ')
                    cout << tempConsonant << "ay" << endl;
            }
            return;
        }

        // this covers the end of the word condition
        if (isInWord)
        {// covers the condition of index [i] being the space at the end of the word
            if (phraseLine[i] == ' ')
            {
                // spits out pig latin word, gets you out of the word, flushes the temp consonants array and resets the # of consonants to 0
                cout << tempConsonant << "ay";
                isInWord = 0;
                tempConsonant[0] = '\0';
                numberOfConsonants = 0;
            }
            cout << phraseLine[i] ;

        }
        else
        {//this covers for the first vowel that makes the switch
            if (phraseLine[i] != ' ')
            {// sets the c string to what is in the phraseline at the time and makes it capitalized
                char currentCharacter = phraseLine[i];
                currentCharacter = toupper(currentCharacter);

                // this takes care of the condition that currentCharacter is not a vowel
                if ((currentCharacter != 'A') && (currentCharacter != 'E') &&
                    (currentCharacter != 'I') && (currentCharacter != 'O') && (currentCharacter != 'U'))
                    //this sets the array to temporarily hold the consonants for display before the 'ay'
                {//this sets the null operator at the end of the c string and looks for the next consonant
                    tempConsonant[numberOfConsonants] = phraseLine[i];
                    tempConsonant[numberOfConsonants + 1] = '\0';
                    numberOfConsonants++;
                }
                else
                {// this sets the boolean isInWord to true and displays the phraseline
                    isInWord = 1;
                    cout << phraseLine[i];
                }
            }
            else
            {
                cout << phraseLine[i] ;
            }
        }

        previousCharacter = phraseLine[i];
    }
    return;
}