我没有找到任何东西，我只找到了带有文本字段的表单。
我的问题是：我有两个按钮调用后端php代码（setvote.php）。

$ipid = $row['ipid'];
$confirmed = 0;
$fake = 0;
if (isset($_POST['confirmedVote'])) {
    $confirmed = 1;
} else if (isset($_POST['fakeVote'])) {
    $fake = 1;
} else {

}

if ($confirmed + $fake == 1){
 $sqlInsert = 'INSERT INTO database (postid, ipid, confirmed, fake) values 
   ('.$id.', '.$ipid.', '.$confirmed.', '.$fake.')';
   $dbInsert = mysqli_Query($connection, $sqlInsert);
}

这是index.php中的表单

//FORM
    if ($countIpVoted == 0) {
        echo '<br>'.'<form name="myform" action="setvote.php" method="POST" >';
        echo '<input type="hidden" name="postId" value="'.$postid.'" />';
        echo '<button class="votetrue" type="submit" name="confirmedVote" id="trues"><i class="fa fa-check" aria-hidden="true"></i> True</button>';
        echo '<button class="votefalse" type="submit" name="fakeVote" id="falses"><i class="fa fa-times" aria-hidden="true"></i> False</button>';
        echo'</form>';
    }
    else {
        echo '<p style="padding-top:6px; padding-bottom:6px;">You have already voted this post.</p>';
        $rowIpVoted = $resultIpVoted->fetch_assoc();

如何将数据发送到mysql而不刷新页面？我试过这样的方法：

<script>
    $(function () {

        $('form').on('submit', function (e) {

            e.preventDefault();

            $.ajax({
                type: 'post',
                url: 'setvote.php',
                data: $('form').serialize(),
                success: function () {

                }
            });

        });

    });
</script>