所以我有疑问:
SELECT t1.username, t1.staff_id, t1.longname, t2.*, t3.longname as appraisor_name, t4.dep, t2.staff_id as check_id, t5.deptname FROM users t1
LEFT JOIN(
SELECT * FROM quartz_quarter2 WHERE staff_id = '1001128' AND date = '2017'
UNION
SELECT * FROM quartz_quarter3 WHERE staff_id = '1001128' AND date = '2017'
UNION
SELECT * FROM quartz_quarter4 WHERE staff_id = '1001128' AND date = '2017'
UNION
SELECT * FROM quartz_quarter1 WHERE staff_id = '1001128' AND date = '2018'
)t2 ON t1.staff_id = t2.staff_id
LEFT JOIN( SELECT * FROM users )t3 ON t2.appraisor_id = t3.staff_id
LEFT JOIN( SELECT * FROM quartz_department )t4 ON t2.role = t4.role
LEFT JOIN( SELECT * FROM ref_department )t5 ON t1.fkdeptid = t5.deptid
WHERE t1.staff_id = '1001128'
我希望以与我选择的顺序完全相同的顺序获取数据,因此应该是:
| username | staff_id | quarter |
+++++++++++++++++++++++++++++++++
| YEVGENIY | 1001128 | 2 |
| YEVGENIY | 1001128 | 3 |
| YEVGENIY | 1001128 | 4 |
| YEVGENIY | 1001128 | 1 |
但我得到的是:
有没有办法根据select语句来排序?
1条答案
按热度按时间pcww981p1#
你可以用这个
FIND_IN_SET()
功能。此函数将返回值在指定集合中的位置。