我正在尝试用一组规则验证jsonobject如果json与一组规则匹配,它将返回匹配的规则,而jsonobject如果不匹配,它将返回一个jsonobject到sideoutput所有这些都是在processFunction中处理的,我得到的是主输出,但无法捕获side输出
sideoutput流定义如下
public final static OutputTag<org.json.JSONObject> unMatchedJSONSideOutput = new OutputTag<org.json.JSONObject>(
"unmatched-side-output") {};
processfunction定义如下
public class RuleFilter extends ProcessFunction<Tuple2<String,org.json.JSONObject>,Tuple2<String,org.json.JSONObject>> {
@Override
public void processElement(Tuple2<String, org.json.JSONObject> value,
ProcessFunction<Tuple2<String, org.json.JSONObject>, Tuple2<String, org.json.JSONObject>>.Context ctx,
Collector<Tuple2<String, org.json.JSONObject>> out) throws Exception {
if(this.value.matches((value.f1))) {
out.collect(new Tuple2<String, org.json.JSONObject>(value.f0,value.f1));
}else {
ctx.output(RuleMatching.unMatchedJSONSideOutput,value.f1);
}
}
}
我正在打印主数据流输出,如下所示
DataStream<Tuple2<String, org.json.JSONObject>> matchedJSON =
inputSignal.map(new MapFunction<org.json.JSONObject, Tuple2<String, org.json.JSONObject>>() {
@Override
public Tuple2<String, org.json.JSONObject> map(org.json.JSONObject input) throws Exception {
return new Tuple2<>(value, input);
}
}).process(new RuleFilter()).print("MatchedJSON=>");
matchedJSON .print("matchedJSON=>");
我打印侧输出如下
DataStream<org.json.JSONObject> unmatchedJSON =
((SingleOutputStreamOperator<org.json.JSONObject>) matchedJSON.map(new MapFunction<Tuple2<String, org.json.JSONObject>, org.json.JSONObject>() {
@Override
public org.json.JSONObject map(Tuple2<String, org.json.JSONObject> value) throws Exception {
return value.f1;
}
})).getSideOutput(unMatchedJSONSideOutput );
unmatchedJSON.print("unmatchedJSON=>");
主流是打印输出,但是sideoutput没有打印无效的json请帮助解决这个问题
1条答案
按热度按时间nc1teljy1#
问题在于:
你应该打电话来
getSideOutput
直接打开matchedJSON
,而不是应用MapFunction
去吧。只有一个ProcessFunction
可以有一个侧输出,它需要直接从ProcessFunction
. 通过从Map中强制转换输出流,您欺骗了编译器接受了这一点,但是运行时无法对此执行任何有意义的操作。