这个问题在这里已经有答案了：

spark sql替换mysql的组concat聚合函数（8个答案）
两年前关门了。
我需要从源表创建一个表（hive table/spark dataframe），该表将多行用户的数据存储到单行列表中。

User table:
Schema:  userid: string | transactiondate:string | charges: string |events:array<struct<name:string,value:string>> 
----|------------|-------| ---------------------------------------
123 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"this"}]
123 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"last"}]
123 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"recent"}]
123 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"0"}]
456 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"this"}]
456 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"last"}]
456 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"recent"}]
456 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"0"}]

输出表应为

userid:String | concatenatedlist :List[Row]
-------|-----------------
123    | [[2017-09-01,20.00,[{"name":"chargeperiod","value":"this"}]],[2017-09-01,30.00,[{"name":"chargeperiod","value":"last"}]],[2017-09-01,20.00,[{"name":"chargeperiod","value":"recent"}]], [2017-09-01,30.00, [{"name":"chargeperiod","value":"0"}]]]
456    | [[2017-09-01,20.00,[{"name":"chargeperiod","value":"this"}]],[2017-09-01,30.00,[{"name":"chargeperiod","value":"last"}]],[2017-09-01,20.00,[{"name":"chargeperiod","value":"recent"}]], [2017-09-01,30.00, [{"name":"chargeperiod","value":"0"}]]]

spark版本：1.6.2