如果要聚合的记录数很高，并且您不想硬编码它。
创建一个将返回数字序列的自定义项

[prjai@lnx0689 py_ws]$ cat prime_num.py
import sys
    try:
            for line in sys.stdin:
                    num = int(line)
                    for i in range(1, num+1):
                            #print u"i".encode('utf-8')
                            print u"%i".encode('utf-8') %(i)
    except:
            print sys.exc_info()

将python脚本添加到配置单元环境

hive> add FILE /home/prjai/prvys/py_ws/prime_num.py

为上述脚本创建临时表

hive> create temporary table t1 as with t1 as (select transform(10) using 'python prime_num.py' as num1) select * from t1;

你的问题是-

hive> with t11 as (select 'A' as event, 3 as count) select t11.event,  t11.count from t11, t1 where t11.count>=t1.num1;

希望这有帮助。

一种方法是创建一个数字表并使用它进行分解。

--create numbers table
create table if not exists dbname.numbers 
location 'some_hdfs_location' as 
select stack(5,1,2,3,4,5) t as num --increase the number of values as needed
--Disaggregation
select a.event,n.num --or a.cnt
from dbname.agg_table a 
join dbname.numbers n on true
where a.cnt >= n.num and a.cnt <= n.num

使用 space() 可以转换的函数 count 要创建长度为count-1的空格字符串，请使用 split() 将其转换为数组和 explode() 与 lateral view 生成行。只需更换 a 在我的演示子查询与您的表。
演示：

select a.event, 
       1 as count --calculate count somehow if necessary
from
    (select stack(2,'A',3,'B',2) as (event, count)) a --Replace this subquery with your table name
    lateral view explode(split(space(a.count-1),' ')) s
;

结果：

OK
A       1
A       1
A       1
B       1
B       1
Time taken: 0.814 seconds, Fetched: 5 row(s)