按照前面关于这个问题的答案,我尝试在弹出窗口中设置动画,但没有成功:
弹出\u anim\u show.xml
<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android">
<scale
android:duration="3000"
android:fromXScale="1"
android:fromYScale="1"
android:pivotX="50%"
android:pivotY="50%"
android:toXScale="5"
android:toYScale="5" />
</set>
弹出动画隐藏.xml
<set xmlns:android="http://schemas.android.com/apk/res/android">
<scale
android:startOffset="5000"
android:duration="3000"
android:fromXScale="1"
android:fromYScale="1"
android:pivotX="50%"
android:pivotY="50%"
android:toXScale="0"
android:toYScale="0" />
</set>
内部valuse\themes\xml
<style name="popup_window_animation" parent="android:Animation">
<item name="android:windowEnterAnimation">@anim/popup_anim_show</item>
<item name="android:windowExitAnimation">@anim/popup_anim_hide</item>
</style>
在通过按下按钮调用的函数中
private void explain(View v) {
LayoutInflater inflater = (LayoutInflater)getSystemService(LAYOUT_INFLATER_SERVICE);
View popupView = inflater.inflate(R.layout.popup_view, null);
// create the popup window
int width = LinearLayout.LayoutParams.WRAP_CONTENT;
int height = LinearLayout.LayoutParams.WRAP_CONTENT;
PopupWindow popupWindow = new PopupWindow(popupView, width, height, true);
popupWindow.setAnimationStyle(R.style.popup_window_animation);
popupWindow.showAtLocation(v, Gravity.TOP, 0, 300);
popupWindow.setFocusable(true);
popupWindow.update();
}
弹出窗口以标准方式显示并忽略我设置的动画。。。请告诉我我做错了什么?
暂无答案!
目前还没有任何答案,快来回答吧!