我使用了下面的代码，它执行时没有任何错误。但拖放操作没有发生。

JavascriptExecutor js = (JavascriptExecutor) driver;
    js.executeScript("function createEvent(typeOfEvent) {\n" + "var event =document.createEvent(\"CustomEvent\");\n"
            + "event.initCustomEvent(typeOfEvent,true, true, null);\n" + "event.dataTransfer = {\n" + "data: {},\n"
            + "setData: function (key, value) {\n" + "this.data[key] = value;\n" + "},\n"
            + "getData: function (key) {\n" + "return this.data[key];\n" + "}\n" + "};\n" + "return event;\n"
            + "}\n" + "\n" + "function dispatchEvent(element, event,transferData) {\n"
            + "if (transferData !== undefined) {\n" + "event.dataTransfer = transferData;\n" + "}\n"
            + "if (element.dispatchEvent) {\n" + "element.dispatchEvent(event);\n"
            + "} else if (element.fireEvent) {\n" + "element.fireEvent(\"on\" + event.type, event);\n" + "}\n"
            + "}\n" + "\n" + "function simulateHTML5DragAndDrop(element, destination) {\n"
            + "var dragStartEvent =createEvent('dragstart');\n" + "dispatchEvent(element, dragStartEvent);\n"
            + "var dropEvent = createEvent('drop');\n"
            + "dispatchEvent(destination, dropEvent,dragStartEvent.dataTransfer);\n"
            + "var dragEndEvent = createEvent('dragend');\n"
            + "dispatchEvent(element, dragEndEvent,dropEvent.dataTransfer);\n" + "}\n" + "\n"
            + "var source = arguments[0];\n" + "var destination = arguments[1];\n"
            + "simulateHTML5DragAndDrop(source,destination);", from1, to1);