我正在尝试使用hibernate和maven建立双向多人关系,但它总是抛出org.hibernate.lazyinitializationexception:无法初始化代理-无会话或StackOverflower错误。我已经尝试过@jsonidentityinfo,结果maven自动添加了一个“pk”变量,这主要破坏了我的前端@jsonmanagedreference和@jsonbackreference,这导致接收到backreference的实体被完全忽略了@jsonignore,backreference的问题与@jsonview相同,它看起来什么都没有改变,和带有自定义序列化程序的@jsonserialize,这在实现时也会导致前端出现问题。我还尝试自己直接将查询连接到存储库中,但它导致了相同的问题。我真的力不从心了,不知道还能做什么。
节点
import com.fasterxml.jackson.annotation.JsonBackReference;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonView;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import de.sadgmbh.spring.angular.backenddemo.model.AbstractAuditingEntity;
import lombok.Getter;
import lombok.NoArgsConstructor;
import lombok.Setter;
import javax.persistence.*;
import javax.validation.constraints.NotNull;
import java.util.HashSet;
import java.util.Set;
@Getter
@Setter
@NoArgsConstructor
@JsonIgnoreProperties(ignoreUnknown = true)
@JsonInclude(JsonInclude.Include.NON_NULL)
@Entity
@Table(name = "knotenpunkte")
//@JsonSerialize(using = CustomKnotenpunktSerializer)
public class Knotenpunkt extends AbstractAuditingEntity<Long> {
@NotNull
@Column(length = 50, unique = true, nullable = false)
@JsonView(Views.Public.class)
private int knotennr;
@NotNull
@Column(length = 50, unique = true, nullable = false)
@JsonView(Views.Public.class)
private String strasse;
@NotNull
@JsonView(Views.Public.class)
private boolean codierung;
@NotNull
@JsonView(Views.Public.class)
private boolean bake;
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(
name = "knotenpunkt_linie",
joinColumns = {@JoinColumn(name = "knotenpunkt_id", referencedColumnName = "id")},
inverseJoinColumns = {@JoinColumn(name = "linie_id", referencedColumnName = "id")})
@JsonView(Views.Internal.class)
Set<Linie> linienSet = new HashSet<>();
}
线
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonView;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import de.sadgmbh.spring.angular.backenddemo.model.AbstractAuditingEntity;
import lombok.Getter;
import lombok.NoArgsConstructor;
import lombok.Setter;
import javax.persistence.*;
import javax.validation.constraints.NotNull;
import java.util.HashSet;
import java.util.Set;
@Getter
@Setter
@NoArgsConstructor
@JsonIgnoreProperties(ignoreUnknown = true)
@JsonInclude(JsonInclude.Include.NON_NULL)
@Entity
@Table(name = "linien")
//@JsonSerialize(using = CustomLineSerializer.class)
public class Linie extends AbstractAuditingEntity<Long> {
@NotNull
@Column(length = 50, unique = true, nullable = false)
@JsonView(Views.Public.class)
private String linienNR;
@ManyToMany( mappedBy = "linienSet")
@JsonView(Views.Internal.class)
private Set<Knotenpunkt> knotenpunktSet = new HashSet<>();
}
maven生成的接口
export interface Knotenpunkt extends AbstractAuditingEntity<number> {
id: number;
knotennr: number;
strasse: string;
codierung: boolean;
bake: boolean;
linienSet: Linie[];
}
export interface Linie extends AbstractAuditingEntity<number> {
id: number;
linienNR: string;
knotenpunktSet: Knotenpunkt[];
}
export interface Views {
}
export interface Internal extends Public {
}
export interface Public {
}
export interface JsonSerializer<T> extends JsonFormatVisitable {
unwrappingSerializer: boolean;
delegatee: JsonSerializer<any>;
}
暂无答案!
目前还没有任何答案,快来回答吧!