我的问题是:当我在“ Postman ”应用程序中创建post请求时。这就是我想贴的
{"name": "John Doe", "email":"jdoe@test.com", "city": "London"}
我得到以下错误:
{
"timestamp": "2018-11-19T20:16:00.486+0000",
"status": 500,
"error": "Internal Server Error",
"message": "could not read a hi value - you need to populate the table: hibernate_sequence; nested exception is org.hibernate.id.IdentifierGenerationException: could not read a hi value - you need to populate the table: hibernate_sequence",
"path": "/api/ver01/product"
}
我在搜索框里寻找答案,但没有人帮我。所以我认为问题出在sql代码中,但我不确定。整个项目是用intellijide编写的。
这是我的产品类。
package com.hubertkulas.webstore.store.archetype;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import java.math.BigDecimal;
import java.sql.Date;
@Entity
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
public class Product {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private boolean contact;
private String email;
private String category;
private String name;
private String city;
private String model;
private BigDecimal price;
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM-dd-yyyy")
private Date date;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getCategory() {
return category;
}
public void setCategory(String category) {
this.category = category;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
public BigDecimal getPrice() {
return price;
}
public void setPrice(BigDecimal price) {
this.price = price;
}
public Date getDate() {
return date;
}
public void setDate(Date date) {
this.date = date;
}
public boolean isContact() {
return contact;
}
public void setContact(boolean contact) {
this.contact = contact;
}
public Long getId() {
return id;
}
// setter for id because Jackson will use it
public void setId(Long id) {
this.id = id;
}
}
这是我的productcontroller类
package com.hubertkulas.webstore.store.controllers;
import com.hubertkulas.webstore.store.archetype.Product;
import com.hubertkulas.webstore.store.jparepository.ProductRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.*;
import java.util.List;
@RestController
@RequestMapping("api/ver01/product")
public class ProductController {
//injecting ProductRepository when ProductController is called
@Autowired
private ProductRepository productRepository;
@GetMapping
public List<Product> list() {
//finds all of the records and returns it
return productRepository.findAll();
}
@PostMapping
@ResponseStatus(HttpStatus.OK)
public void create(@RequestBody Product product){
productRepository.save(product);
}
@GetMapping("/{id}")
public Product get(@PathVariable("id") long id){
// return specific record with added id
return productRepository.getOne(id);
}
}
这是我的productrepository接口
package com.hubertkulas.webstore.store.jparepository;
import com.hubertkulas.webstore.store.archetype.Product;
import org.springframework.data.jpa.repository.JpaRepository;
//Using Jpa for CRUD operations
public interface ProductRepository extends JpaRepository<Product, Long> {
}
这是我的数据库
CREATE TABLE
product
(
id BIGINT NOT NULL,
contact BOOLEAN NOT NULL,
email VARCHAR,
category VARCHAR,
name VARCHAR,
city VARCHAR,
date DATETIME,
price NUMERIC,
model VARCHAR,
PRIMARY KEY (id)
);
CREATE TABLE
hibernate_sequence
(
next_val BIGINT
);
INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (1, 1, 'abraham@site.com', 'Electronics', 'Abraham Westbrom', 'New
York', 4419619200000, '3250');
INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (2, 1, 'udon@site.com', 'Electronics', 'Udon Hon', 'London',
4419619200000, '799');
INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (3, 0, 'mateuszsinus@site.com', 'Software', 'Mateusz Sinus',
'Warsaw', 4419619200000, '10000');
INSERT INTO hibernate_sequence (next_val) VALUES (4);
3条答案
按热度按时间mqxuamgl1#
您可以添加
在application.yml文件或application.properties文件中,只有在截断了表或可以添加
INSERT INTO <schema_name>.hibernate_sequence (next_val) VALUES (1);
uyhoqukh2#
如果您使用springboot为本地数据库创建模式,并且jpa被配置为执行自动create drop,那么理想情况下您不会遇到这种情况。
但在暂存/生产中,您需要单独处理模式定义(ddl),因此hibernate\u序列需要有一个初始值,0应该足以启动。它告诉程序库从哪个数字开始自动生成id。
上面的一个适用于mysql
m2xkgtsf3#
你的
hibernate_sequence
table不对。见2.6.10。使用标识符表: