这就像矩阵转置。可以在循环中使用循环，也可以在流中使用流：

int d = 4;
int[][] arr1 = {
        {5, 10, 8, 9},
        {16, 30, 25, 41},
        {7, 17, 50, 12},
        {45, 8, 22, 34}
};

int[][] arr2 = new int[d][d];
int[][] arr3 = new int[d][d];
int[][] arr4 = new int[d][d];

IntStream.range(0, d).forEach(i ->
        IntStream.range(0, d).forEach(j -> {
            // matrix transpose
            arr2[j][i] = arr1[i][j];
            // turn matrix 90º clockwise
            arr3[j][d - 1 - i] = arr1[i][j];
            // turn matrix 90º counterclockwise
            arr4[d - 1 - j][i] = arr1[i][j];
        }));

Arrays.stream(arr4).map(Arrays::toString).forEach(System.out::println);
// [9, 41, 12, 34]
// [8, 25, 50, 22]
// [10, 30, 17, 8]
// [5, 16, 7, 45]

每个细胞 [i][j] 原来的矩阵变成了一个细胞 [4-1-j][i] 在旋转矩阵中：

int d = 4;
int[][] arr1 = {
        {5, 10, 8, 9},
        {16, 30, 25, 41},
        {7, 17, 50, 12},
        {45, 8, 22, 34}};
int[][] arr2 = new int[d][d];

for (int i = 0; i < d; i++)
    for (int j = 0; j < d; j++)
        arr2[d - 1 - j][i] = arr1[i][j];

for (int row = 0; row < d; row++)
    System.out.println(Arrays.toString(arr2[row]));
// [9, 41, 12, 34]
// [8, 25, 50, 22]
// [10, 30, 17, 8]
// [5, 16, 7, 45]

另请参见：
•如何逆时针旋转矩阵90度？
•是否有方法反转多维数组中的特定数组？