如何在kotlin/java中对同一方法调用进行排队

sxissh06 于 2021-06-30 发布在 Java

关注(0)|答案(1)|浏览(361)

我使用diffutil计算recyclerview中的数据更改。计算是在调度程序线程上使用rxjava异步完成的，如下所示：

fun setResultItems(list: List<FlightResultItem>?) {
    Log.d("debugfilter", "            setResultItems of size: " + (list?.size?: 0))
    list?.let { newList ->
        Single.fromCallable { DiffUtil.calculateDiff(ResultItemDiffUtilCallback(ArrayList(newList), ArrayList(resultItems))) }
                .subscribeOn(Schedulers.io())
                .observeOn(AndroidSchedulers.mainThread())
                .subscribe { diffResult ->
                    Log.d("debugfilter", "            setResultItems AFTER DIFF of size: " + (newList.size))
                    resultItems = ArrayList(newList)
                    diffResult.dispatchUpdatesTo(this)

                }.also { mCompositeSubscription?.add(it) }
    }
}

当函数连续调用时，大数据集的计算将最后完成

D: debugfilter : setResultItems of size: 113 
D: debugfilter : setResultItems of size: 7 
D: debugfilter : setResultItems AFTER DIFF of size: 7 
D: debugfilter : setResultItems AFTER DIFF of size: 113

有没有办法将方法调用排队，等待执行完成，然后再执行另一个方法调用？

Java android android-recyclerview rx-java android-diffutils

来源：https://stackoverflow.com/questions/63717053/how-to-queue-the-same-method-call-in-kotlin-java

1条答案

按热度按时间

vngu2lb81#

我认为可以使用scheduler.single（）创建单线程工作线程。它将按顺序处理请求。

fun setResultItems(list: List<FlightResultItem>?) {
Log.d("debugfilter", "            setResultItems of size: " + (list?.size?: 0))
list?.let { newList ->
    Single.fromCallable { DiffUtil.calculateDiff(ResultItemDiffUtilCallback(ArrayList(newList), ArrayList(resultItems))) }
        .subscribeOn(Schedulers.single())
        .observeOn(AndroidSchedulers.mainThread())
        .subscribe { diffResult ->
            Log.d("debugfilter", "            setResultItems AFTER DIFF of size: " + (newList.size))
            resultItems = ArrayList(newList)
            diffResult.dispatchUpdatesTo(this)

        }.also { mCompositeSubscription?.add(it) }
}
}

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如何在kotlin/java中对同一方法调用进行排队

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