我在试着 csv_url , start_date 值并将其保存在json中的一个变量中，请建议正确的方法。
[{"csv_url":"https://cdn.rawgit.com/everypolitician/everypolitician-data/f1541f4f2f494697bf8807518d8fbcda4ee8b505/data/Aland/Lagting/term-2015.csv","csv":"data/Aland/Lagting/term-2015.csv","name":"2015u20132019","id":"term/2015","slug":"2015","start_date":"2015-11-02"},{"end_date":"2015","csv_url":"https://cdn.rawgit.com/everypolitician/everypolitician-data/d8862e4d2d7d66d8cee83d2aefc97172f26ac594/data/Aland/Lagting/term-2011.csv","csv":"data/Aland/Lagting/term-2011.csv","name":"2011u20132015","id":"term/2011","slug":"2011","start_date":"2011"},{"end_date":"2011","csv_url":"https://cdn.rawgit.com/everypolitician/everypolitician-data/d8862e4d2d7d66d8cee83d2aefc97172f26ac594/data/Aland/Lagting/term-2007.csv","csv":"data/Aland/Lagting/term-2007.csv","name":"2007u20132011","id":"term/2007","slug":"2007","start_date":"2007"}]
我想要
String[] url = {"csv_url" : "values ","start_date":"2015-11-02"};
1条答案
按热度按时间hmtdttj41#
@javide是对的，您可以使用gson易于使用的库来解析json响应。
你可以去http://www.jsonschema2pojo.org/，粘贴json响应并选择json，然后命名类，这将创建将json解析为pojo所需的类和方法。之后，您可以遍历列表并获得所需的值。
这有助于：将pojo对象放入jtable
这些教程系列可以帮助您了解如何反序列化json响应：https://www.youtube.com/watch?v=bbi8fdqokns