这个问题在这里已经有答案了：

如果用户为scanner的next（）输入两个单词，则第二个单词将被传输到nextint（）方法，该方法随后会导致inputmismatchexception（4个答案）
扫描仪在使用next（）或nextfoo（）后跳过nextline（）(21个答案）
23天前关门了。
当我试图输入一个类别名称时，如果我没有在要添加到变量category的字符串中添加空格，它就会工作。我试着扫描nextline（），它只是跳过了所有的类别输入。让我知道你的想法。谢谢

public static void main(String[] args) 
{
    Scanner scan = new Scanner(System.in);

    //*********************************************************************
    //  Enter the amount of grading categories used in grading
    //          and create an array to store grading percentages
    //*********************************************************************
    System.out.println("Enter how many grade percentage "
            + "caterogies there are:");
    int numCategories = scan.nextInt();
    double [] gradePercentages = new double [numCategories];
    double [] finalGrades = new double [numCategories];

    for (int i=0;i<numCategories;i++) 
    {
        //**********************************************************************
        //  Enter the data for category 1
        //**********************************************************************
            System.out.println("Enter the category name:");
          **String category = scan.next();**
            System.out.println("Enter category percentage:");
            gradePercentages[i] = scan.nextInt();

//**

// - Compiler:

//**
//Enter how many grade percentage caterogies there are:
//5
//Enter the category name:
//Section Quizzes
//Enter category percentage:
//Exception in thread "main" java.util.InputMismatchException
//at java.base/java.util.Scanner.throwFor(Scanner.java:939)
//at java.base/java.util.Scanner.next(Scanner.java:1594)
//at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
//at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
//at GradeCalculator.main(GradeCalculator.java:30)