首先-这是我的部分代码：

public void run() {
            try {
            _conn = new SmtpConnection(this, _socket);
            _state = new SmtpState(_workspace);
            _quitting = false;
            sendGreetings();
                while (!_quitting)
                handleCommand();
        } catch (SocketTimeoutException ste) {
            _conn.send("421 Service shutting down and closing transmission channel");
        } catch (Exception e) {
            // Closing socket on blocked read
            if (!_quitting) {
                log.error("Unexpected error handling connection, quitting=", e);
                throw new IllegalStateException(e);
            }
        } finally {
            if (null != _state) {
                _state.clearMessage();
            }
        }
    }

我在另一个类中还有一个函数，叫做timeoutonemail

public boolean timeoutOnNextEmail()
{
    boolean timeout = true;
    return timeout;
}

我有一个unittest，它应该尝试发送电子邮件，但是当我调用timeoutfuntion时，测试应该通过-所以它不应该发送电子邮件

/*    @Test(expected = MailException.class)
public void sendEmailFail() throws MailException {
    greenMail.timeoutOnNextEmail();
    try {
        app.sendMail("to", "from", "subject", "body");
    } catch (final MailException e) {
        throw new MailException(e.toString());
    } catch (InterruptedException e) {
        e.printStackTrace();
    }
    assertEquals(0, greenMail.getReceivedMessagesForDomain("to").length);
}*/

我如何告诉我的run函数，如果我在unittest中调用timeoutfuntion，那么它应该停止这样做，让我的线程休眠。。我试过类似的方法

* /*                    if(timeout && !_quitting){
                greenMail.timeoutOnNextEmail();
                try {
                    Thread.sleep(1000);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            else
            {
                handleCommand();
            }*/*

还有几个不同的选择，但我不知道怎么正确地称呼它。。