我有一个很小很可能很愚蠢的问题。我不知道该怎么走。我想弄清楚如何转换一个整数，以便像下面的单元测试那样打印出一个字符串。我不允许使用枚举，因为确切的问题要求它表示为整数。我需要hashmap，还是只需要简单的switch语句？当我运行单元测试时，我需要它打印出来：

Cat (Ragdoll: House Cat) is 1 year old, is 30 units fast.

但目前正在打印：

Cat (Ragdoll: 3) is 1 year old, is 30 units fast.

cat类（我删除了不相关的方法）：

public class Cat extends Animal { 

    private Integer type;
    private String breed;

    static final Integer LION = 1;
    static final Integer TIGER = 2;
    static final Integer HOUSE_CAT = 3;
    static final Integer PUMA = 4;

    public Cat(int age, int speed, Integer type, String breed){
        super(age, speed);
        this.type = type;
        this.breed = breed;
    }

    public String getBreed() {
        return breed;
    }

    public Integer getType() {
        return type;
    }

    public String toString() {
        return ("Cat (" + breed + ": " + type + ")" + super.toString());

    }

}

单元测试（可以在dog类中使用枚举，因此没有问题）。

@Test
    void testAllParts() {
        Animal dog = new Dog(12, 30, Dog.type.GUNDOG, "Irish Setter");
        Animal cat = new Cat(1, 30, Cat.HOUSE_CAT, "Ragdoll");

        assertTrue(dog.isOlder(cat));
        assertFalse(cat.isOlder(dog));

        assertFalse(dog.isFaster(cat));
        assertFalse(cat.isFaster(dog));

        assertEquals("Dog (Irish Setter: GUNDOG) is 12 years old, is 30 units fast.", dog.toString());
        assertEquals("Cat (Ragdoll: House Cat) is 1 year old, is 30 units fast.", cat.toString());

        assertFalse(dog.equals(cat));

        Animal [] a = dog.multiply(2);
        assertEquals(a[0], a[1]);
        assertFalse(dog.equals(a[0]));
        assertEquals(2, a.length);

        a = cat.multiply(2);
        assertEquals(a[0], a[1]);
        assertFalse(cat.equals(a[0]));
        assertEquals(2, a.length);

    }