在下面的示例代码中，我很难理解“apply”方法的用法。apply方法到底在做什么，因为它没有被覆盖？很明显是在返回结果 ValidationResult ，但没有代码支持它。

public class Main {
    public static void main(String[] args) {
        Customer customer = new Customer("Alice", "alice@gmail.com", "0879546451", LocalDate.of(2000, 1, 1));
        ValidationResult result = CustomerRegistrationValidator
        .isEmailValid()
        .and(CustomerRegistrationValidator.isPhoneNumber())
        .and(CustomerRegistrationValidator.isAdult())
        .apply(customer);
        System.out.println(result);
    }
}
public interface CustomerRegistrationValidator extends Function<Customer, ValidationResult> {
    static CustomerRegistrationValidator isEmailValid() {
        return customer -> customer.getEmail().contains("@") ? ValidationResult.SUCCESS : ValidationResult.EMAIL_NOT_VALID;
    }
    static CustomerRegistrationValidator isPhoneNumber() {
        return customer -> customer.getPhoneNumber().contains("+08") ? ValidationResult.SUCCESS : ValidationResult.PHONE_NUMER_NOT_VALID;
    }
    static CustomerRegistrationValidator isAdult() {
        return customer -> Period.between(customer.getDob(), LocalDate.now()).getYears() > 16 ? ValidationResult.SUCCESS : ValidationResult.IS_NOT_AN_ADULT;
    }
    default CustomerRegistrationValidator and (CustomerRegistrationValidator other) {
        return customer -> {
            ValidationResult result = this.apply(customer);
            return result.equals(ValidationResult.SUCCESS) ? other.apply(customer) : result;
        };
    }
    enum ValidationResult {
        SUCCESS, PHONE_NUMER_NOT_VALID, EMAIL_NOT_VALID, IS_NOT_AN_ADULT;
    } 
}