我对spring还很陌生,在oauth对服务器进行身份验证时,我一直在尝试捕获未经授权的异常。我不明白为什么handleresponseerror()方法没有捕获异常。
我得到的线索是:
org.springframework.security.oauth2.client.ClientAuthorizationException: [invalid_client] Client authentication failed
at org.springframework.security.oauth2.client.ClientCredentialsReactiveOAuth2AuthorizedClientProvider.lambda$authorize$0(ClientCredentialsReactiveOAuth2AuthorizedClientProvider.java:82)
Suppressed: reactor.core.publisher.FluxOnAssembly$OnAssemblyException:
Error has been observed at the following site(s):
|_ checkpoint ⇢ Request to GET https://localhost:8181/catalog/NL/brands?language_code=nl [DefaultWebClient]
Stack trace:
at org.springframework.security.oauth2.client.ClientCredentialsReactiveOAuth2AuthorizedClientProvider.lambda$authorize$0(ClientCredentialsReactiveOAuth2AuthorizedClientProvider.java:82)
at reactor.core.publisher.Mono.lambda$onErrorMap$29(Mono.java:3272)
at reactor.core.publisher.Mono.lambda$onErrorResume$31(Mono.java:3362)
at reactor.core.publisher.FluxOnErrorResume$ResumeSubscriber.onError(FluxOnErrorResume.java:88)
at reactor.core.publisher.FluxHide$SuppressFuseableSubscriber.onError(FluxHide.java:132)
at reactor.core.publisher.MonoFlatMap$FlatMapMain.secondError(MonoFlatMap.java:185)
at reactor.core.publisher.MonoFlatMap$FlatMapInner.onError(MonoFlatMap.java:251)
at reactor.core.publisher.FluxMapFuseable$MapFuseableSubscriber.onError(FluxMapFuseable.java:134)
at reactor.core.publisher.FluxMapFuseable$MapFuseableSubscriber.onError(FluxMapFuseable.java:134)
at reactor.core.publisher.MonoFlatMap$FlatMapMain.onNext(MonoFlatMap.java:135)
at reactor.core.publisher.FluxMap$MapSubscriber.onNext(FluxMap.java:114)
at reactor.core.publisher.FluxSwitchIfEmpty$SwitchIfEmptySubscriber.onNext(FluxSwitchIfEmpty.java:67)
at reactor.core.publisher.FluxOnErrorResume$ResumeSubscriber.onNext(FluxOnErrorResume.java:73)
at reactor.core.publisher.Operators$MonoSubscriber.complete(Operators.java:1782)
at reactor.core.publisher.MonoFlatMap$FlatMapMain.onNext(MonoFlatMap.java:144)
要向服务器进行身份验证的代码:
@Bean
public WebClient myClient() {
InMemoryReactiveClientRegistrationRepository clientRegistryRepo = new InMemoryReactiveClientRegistrationRepository(getClientRegistration());
InMemoryReactiveOAuth2AuthorizedClientService clientService = new InMemoryReactiveOAuth2AuthorizedClientService(clientRegistryRepo);
AuthorizedClientServiceReactiveOAuth2AuthorizedClientManager authorizedClientManager = new AuthorizedClientServiceReactiveOAuth2AuthorizedClientManager(clientRegistryRepo, clientService);
ServerOAuth2AuthorizedClientExchangeFilterFunction oauthFilter = new ServerOAuth2AuthorizedClientExchangeFilterFunction(authorizedClientManager);
oauthFilter.setDefaultClientRegistrationId(OAUTH_PROVIDER_NAME);
return WebClient.builder()
.clientConnector(new JettyClientHttpConnector(createHttpClient()))
.exchangeStrategies(getMaxMessageInMemorySize(maxInMemorySize))
.baseUrl(baseURL)
.filter(oauthFilter)
.filter(handleResponseError())
.build();
}
private static ExchangeFilterFunction handleResponseError() {
return ExchangeFilterFunction.ofResponseProcessor(
response -> response.statusCode().isError() ?
response.bodyToMono(String.class)
.flatMap(errorBody -> Mono.error(new MyUnAuthorizedRequestException(response.statusCode().name(), errorBody, ""))) :
Mono.just(response));
}
我看了各种各样的例子:
如何在SpringWebFlux中的webclient示例化期间设置一次访问令牌?
https://www.baeldung.com/spring-webclient-oauth2
我使用@controlleradvice捕获所有其他异常。这是正确的处理方法吗?
1条答案
按热度按时间svujldwt1#
我找到了解决办法: